php $ 未在 javascript 中定义 ajax 请求
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$ not defined ajax request in javascript
提问by user2793027
I am trying to send a php file some values using ajax but in the call for ajax I am getting the following error
我正在尝试使用 ajax 向 php 文件发送一些值，但在调用 ajax 时出现以下错误
Uncaught ReferenceError: $ is not defined
at the beginning line for the ajax request as follows:
在 ajax 请求的起始行如下：
$.ajax({
type: "POST",
url: 'program3.php',
data: {
player1name: player1name.value,
player2name: player2name.value,
playtopoints: playtopoints.value,
delay: delay.value,
numgames: numgames.value,
gamesplayed: gamesplayed.value,
p1turn: p1turn.value,
p2turn: p2turn.value,
p1total: p1total.value,
p2total: p2total.value
},
success: function (data) {
rolling = data;
}
});
I first thought that it might need the refrence to ajax so i added the following line before the javascript on the html page:
我首先认为它可能需要对 ajax 的引用，所以我在 html 页面上的 javascript 之前添加了以下行：
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
but i am still getting the erro can anyone offer any insight?
但我仍然得到错误任何人都可以提供任何见解吗？
Also i have the data variables all defined as follow:
我也有数据变量都定义如下：
var player1name = document.JForm.p1name.innerHTML;
is that the correct way to assign them?
这是分配它们的正确方法吗？
回答by Adam Rackis
The srcon your script tag is invalid—at least if you're not running this from http or https. Replace
的src，如果你在你的脚本标签是无效的，至少不是从HTTP或HTTPS运行此。代替
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
with
和
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
回答by hexacyanide
You are probably accessing the file locally, which won't work with a protocol-relative script tag.
您可能正在本地访问该文件，这不适用于与协议相关的脚本标记。
<!-- access from http resolves to this -->
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<!-- local access resolves to this -->
<script src="file://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
The file wouldn't have existed locally, and the script would've never been loaded. Therefore, the variable $would then be undefined.
该文件不会在本地存在，脚本也不会被加载。因此，该变量$将是未定义的。
