C# 抛出异常后继续循环迭代
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Continue loop iteration after exception is thrown
提问by Dimitar Tsonev
Let's say I have a code like this:
假设我有这样的代码：
try
{
for (int i = 0; i < 10; i++)
{
if (i == 2 || i == 4)
{
throw new Exception("Test " + i);
}
}
}
catch (Exception ex)
{
errorLog.AppendLine(ex.Message);
}
Now, it's obvious that the execution will stop on i==2, but I want to make it finish the whole iteration so that in the errorLoghas two entries (for i==2and i==4)
So, is it possible to continue the iteration even the exception is thrown ?
现在，很明显，执行将停止i==2，但我想让它完成整个迭代，以便在其中errorLog有两个条目（fori==2和i==4）那么，即使抛出异常，是否也可以继续迭代？
采纳答案by Servy
Just change the scope of the catchto be inside the loop, not outside it:
只需将 的范围更改为catch在循环内，而不是在循环外：
for (int i = 0; i < 10; i++)
{
try
{
if (i == 2 || i == 4)
{
throw new Exception("Test " + i);
}
}
catch (Exception ex)
{
errorLog.AppendLine(ex.Message);
}
}
回答by Kenneth
Why do you throw the exception at all? You could just write to the log immediately:
你为什么要抛出异常？您可以立即写入日志：
for (int i = 0; i < 10; i++)
{
if (i == 2 || i == 4)
{
errorLog.AppendLine(ex.Message);
continue;
}
}
