java java正则表达式用破折号替换特殊字符和空格
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java regex replace special characters and spaces with dash
提问by Code Junkie
I have the following string,
我有以下字符串，
String model = "Town & Country";
I'd like to replace the special characters and the spaces with a dash as well as lower case it for a nice clean url.
我想用破折号和小写替换特殊字符和空格，以获得一个干净的网址。
Example
例子
"town-country"
I've tried the following code.
我试过下面的代码。
"Town & Country".replaceAll("[^A-Za-z0-9]", "-").toLowerCase();
but I ended up with the following output.
但我最终得到了以下输出。
town---country
Could someone assist me with the regex so that this works properly? I if there is multiple spaces, I'd like to reduce it to a single space replaced by a dash. If there is a good java library out there designed to do this, I'd be interested in it, however I do not want to use pluses.
有人可以帮助我使用正则表达式以使其正常工作吗？如果有多个空格，我想将其减少为用破折号代替的单个空格。如果有一个很好的 Java 库可以做到这一点，我会对它感兴趣，但是我不想使用加号。
回答by Alexis King
You're close, you just need to add a quantifier to the expression to allow it to match more than one character.
你很接近，你只需要在表达式中添加一个量词，以允许它匹配多个字符。
/[^A-Za-z0-9]+/
(Note the +at the end.)
（注意+最后。）
So, your code should be this:
所以，你的代码应该是这样的：
"Town & Country".replaceAll("[^A-Za-z0-9]+", "-").toLowerCase();
