Scala 2.8 中的包私有修饰符
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时间：2020-10-22 03:49:57 来源:igfitidea点击:
Package private modifier in Scala 2.8
提问by Robin Green
If I try
如果我尝试
private[com.company.foo] def bar(xml: XmlPath) = {
I get
我得到
[error] ... ']' expected but '.' found.
[error] private[com.
[error] ^
What's with that? I can only make it package-private to com.*, or...?
那是怎么回事？我只能将其设置为 com.* 的包私有的，或者...？
回答by Nikita Ignatov
You can only define the enclosing package, within which the code is defined:
您只能定义封闭包，其中定义了代码：
package com.company.foo
class Bar{
private[foo] def bar(xml: XmlPath)
}
and if you want to set it to company:
如果您想将其设置为公司：
private[company] def bar(xml: XmlPath)
