bash 如何忽略 awk 命令中的转义序列警告
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How to ignore the escape sequence warning in awk command
提问by user2589079
I using the below command to get the line number for the specific string
我使用下面的命令来获取特定字符串的行号
str_to_search="\/searchString >"
fileName=Myfile.txt
startingCt=$(awk 'gawk '/PATTERN/ {print FNR}' filename
~ str{print NR; exit }' str="$str_to_search" $fileName)
endingCt=$(($startingCt + 3))
echo $startingCt
echo $endingCt
I am able to get the line numbers but i am getting the warning message for escape sequence as
我能够获得行号，但我收到了转义序列的警告消息
awk: cmd. line:1: warning: escape sequence
\/' treated as plain/'
awk：cmd。第 1 行：警告：转义序列
\/' treated as plain/'
Please let me know if there is any way to ignore the warnings for escape sequence and is there any better way of getting the line number. Thanks in advance.
请让我知道是否有任何方法可以忽略转义序列的警告，以及是否有更好的方法来获取行号。提前致谢。
回答by Oz123
The problem is probably related to your awk version.
问题可能与您的 awk 版本有关。
See the link here: http://ubuntuforums.org/showthread.php?t=474549
请参阅此处的链接：http: //ubuntuforums.org/showthread.php?t=474549
Here is way with AWK:
这是 AWK 的方法：
sed -n '/pattern/=' filename
May I also offer this solution, although it's not using awk?
我也可以提供这个解决方案，虽然它没有使用 awk？
##代码##Sed and AWK kind of like cute brothers, you will find some kind of version of them on many systems, and the share a lot of features, but with different ways of using them.
sed 和 AWK 有点像可爱的兄弟，你会在很多系统上找到它们的某种版本，并且共享很多功能，但是使用它们的方式不同。
The above command will output only the line number of the pattern you are looking for.
上面的命令将只输出您正在寻找的模式的行号。
