检测到 Swig/Python 内存泄漏
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Swig / Python memory leak detected
提问by
I have a very complicated class for which I'm attempting to make Python wrappers in SWIG. When I create an instance of the item in Python, however, I'm unable to initialize certain data members without receiving the message:
我有一个非常复杂的类，我试图在 SWIG 中为它制作 Python 包装器。但是，当我在 Python 中创建项目的实例时，我无法在未收到消息的情况下初始化某些数据成员：
>>> myVar = myModule.myDataType()
swig/python detected a memory leak of type 'MyDataType *', no destructor found.
Does anyone know what I need to do to address this? Is there a flag I could be using to generate destructors?
有谁知道我需要做什么来解决这个问题？有没有我可以用来生成析构函数的标志？
回答by ASk
SWIG always generates destructor wrappers (unless %nodefaultdtordirective is used). However, in case where it doesn't know anything about a type, it will generate an opaque pointer wrapper, which will cause leaks (and the above message).
SWIG 始终生成析构函数包装器（除非使用%nodefaultdtor指令）。但是，如果它对某个类型一无所知，它将生成一个不透明的指针包装器，这将导致泄漏（以及上述消息）。
Please check that myDataTypeis a type that is known by SWIG. Re-run SWIG with debug messages turned on and check for any messages similar to
请检查这myDataType是 SWIG 已知的类型。在打开调试消息的情况下重新运行 SWIG 并检查是否有任何类似于以下内容的消息
Nothing is known about Foo base type - Bar. Ignored
Receiving a message as above means that SWIG doesn't know your type hierarchy to the full extent and thus operates on limited information - which could cause it to not generate a dtor.
收到上述消息意味着 SWIG 不完全了解您的类型层次结构，因此对有限的信息进行操作 - 这可能导致它不生成 dtor。
回答by hhafez
The error message is pretty clear to me, you need to define a destructor for this type.
错误信息对我来说很清楚，你需要为这种类型定义一个析构函数。
