访问 C# WPF 应用程序中的资源（同一个程序集）
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Accessing Resources in a C# WPF Application (Same Assembly)
提问by Literata
(Before I jump into the nitty-gritty, I want to set the context: I'm trying to load a WPF frame with the contents of an .html file that I'm including in my project as a resource.)
（在我进入细节之前，我想设置上下文：我正在尝试加载一个 WPF 框架，其中包含我作为资源包含在我的项目中的 .html 文件的内容。）
I create a new WPF Application; I add a new folder called 'foofiles' to the project, and I add a couple of files (page1.foo and page2.foo) to that folder.
我创建了一个新的 WPF 应用程序；我向项目添加了一个名为“foofiles”的新文件夹，并向该文件夹添加了几个文件（page1.foo 和 page2.foo）。
For each newly added .foo file, I right-click on it, go to "Properties," and set the Build Action to 'Resource,' and the Copy To Output Directory to "Copy always."
对于每个新添加的 .foo 文件，我右键单击它，转到“属性”，并将“构建操作”设置为“资源”，将“复制到输出目录”设置为“始终复制”。
I want to be able to access those files both in XAML:
我希望能够在 XAML 中访问这些文件：
<Frame x:Name="bar" Source="/foofiles/page1.foo"/>
And in procedural code:
在程序代码中：
private void someFunc()
{
bar.Source = new Uri("/foofiles/page1.foo");
}
But I just can't figure out why this doesn't work -- I get a "Format of the URI could not be determined."
但我就是不明白为什么这不起作用——我得到一个“无法确定 URI 的格式”。
In the code-behind, I tried doing this:
在代码隐藏中，我尝试这样做：
private void someFunc()
{
bar.Source = new Uri("pack://application:,,,/foofiles/page1.foo");
}
which didn't throw an exception, but my main window crashed.
它没有抛出异常，但我的主窗口崩溃了。
In my thinking, if I add a file of any type to my project, and if I mark it as "Resource" in "Build Action," I should be able to use that file per my examples above. Also, I would like to use that file like this:
在我看来，如果我将任何类型的文件添加到我的项目中，并且如果我在“构建操作”中将其标记为“资源”，我应该能够按照上面的示例使用该文件。另外，我想像这样使用该文件：
private void someOtherFunc()
{
System.IO.StreamReader reader = new System.IO.StreamReader("/foofiles/page1.foo");
string bar = reader.ReadToEnd();
}
Any help would be appreciated... thanks in advance!
任何帮助将不胜感激...提前致谢！
回答by mkoertgen
Try adding the component-part to your Pack URI like this
尝试将component-part添加到您的 Pack URI 中
pack://application:,,,/AssemblyName;component/ResourceName
where AssemblyNameis the name of your assembly. So for your case, the following statement should work:
其中AssemblyName是程序集的名称。因此，对于您的情况，以下语句应该有效：
bar.Source = new Uri("pack://application:,,,/AssemblyName;component/foofiles/page1.foo");
More practically, try the relative pack uri notation:
更实际地，尝试使用相对的 pack uri 表示法：
bar.Source = new Uri("AssemblyName;component/foofiles/page1.foo", UriKind.Relative));
For stream reading resources use
对于流阅读资源使用
var streamResourceInfo = Application.GetResourceStream(uri);
using (var stream = streamResourceInfo.Stream)
{
// do fancy stuff with stream
}
