Android 与 HandlerThread 通信的示例

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时间:2020-08-20 09:04:49  来源:igfitidea点击:

Example communicating with HandlerThread

androidmultithreadingandroid-handlerandroid-handlerthread

提问by CL22

I want to set up a HandlerThread from the GUI thread. Then some time later, when a button is clicked on the GUI, it runs callHello(), which then send a message to a HelloLogger object residing on the non-GUI thread which asynchronously logs "Hello World". I have tried a number of things, some block indefinitely, some never receive the message, etc etc. The code below is more or less as close as I have got, please could someone modify it to work?

我想从 GUI 线程设置一个 HandlerThread。然后一段时间后,当单击 GUI 上的按钮时,它会运行 callHello(),然后向驻留在异步记录“Hello World”的非 GUI 线程上的 HelloLogger 对象发送一条消息。我尝试了很多东西,有些无限期地阻止,有些永远不会收到消息等等。下面的代码或多或少与我所得到的一样接近,请有人修改它以使其工作吗?

public class HandlerThreadExample {

    private MyHandlerThread mMyHandlerThread;
    private Looper mLooper;
    private Handler mHandler;

    public HandlerThreadExample(){
        mMyHandlerThread = new MyHandlerThread();
        mMyHandlerThread.start();
        mLooper = mMyHandlerThread.getLooper();
    }
    public void callHello() {
        mHandler.sendEmptyMessage(1);
    }
    private class MyHandlerThread extends HandlerThread {
        private HelloLogger mHelloLogger;
        private Handler mHandler;
        public MyHandlerThread() {
            super("The MyHandlerThread thread", HandlerThread.NORM_PRIORITY);
        }
        public void run (){
            mHelloLogger = new HelloLogger();
            mHandler = new Handler(getLooper()){
                public void handleMessage(Message msg){
                    mHelloLogger.logHello();
                }
            };
            super.run();
        }
    }
    private class HelloLogger {
        public HelloLogger (){
        }
        public void logHello(){
            Log.d("HandlerThreadExample", "Hello World");
        }
    }
}

Best examples found:

发现的最佳示例:

At least now I can close the damned tabs

至少现在我可以关闭该死的标签

Solution courtesy of help from pskink

解决方案由 pskink 提供帮助

public class HandlerThreadExample2 {
    private static int MSG_START_HELLO = 0;
    private static int MSG_HELLO_COMPLETE = 1;
    private HandlerThread ht;
    private Handler mHtHandler;
    private Handler mUiHandler;
    private boolean helloReady = false;
    public HandlerThreadExample2(){
        ht = new HandlerThread("The new thread");
        ht.start();
        Log.d(App.TAG, "UI: handler thread started");
        mUiHandler = new Handler(){
            public void handleMessage(Message msg){
                if (msg.what == MSG_HELLO_COMPLETE){
                    Log.d(App.TAG, "UI Thread: received notification of sleep completed ");
                    helloReady = true;              }
            }
        };
        mHtHandler = new Handler(ht.getLooper()){
            public void handleMessage (Message msg){
                if (msg.what == MSG_START_HELLO){
                    Log.d(App.TAG, "handleMessage " + msg.what + " in " + Thread.currentThread() + " now sleeping");
                    try {
                        Thread.sleep(2000);
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                    Log.d(App.TAG, "Woke up, notifying UI thread...");
                    mUiHandler.sendEmptyMessage(MSG_HELLO_COMPLETE);
                }
            }
        };
    }
    public void sendLongHello(){
        if (helloReady){
            Log.d(App.TAG, "sending hello " + Thread.currentThread());      
            mHtHandler.sendEmptyMessage(MSG_START_HELLO);
            helloReady = false;
        } else {
            Log.e(App.TAG, "Cannot do hello yet - not ready");
        }
    }
}

回答by pskink

This is a working example:

这是一个工作示例:

HandlerThread ht = new HandlerThread("MySuperAwesomeHandlerThread");
ht.start();
Handler h = new Handler(ht.getLooper()) {
    public void handleMessage(Message msg) {
        Log.d(TAG, "handleMessage " + msg.what + " in " + Thread.currentThread());
    };
};
for (int i = 0; i < 5; i++) {
    Log.d(TAG, "sending " + i + " in " + Thread.currentThread());
    h.sendEmptyMessageDelayed(i, 3000 + i * 1000);
}

UPDATE:

更新

Make two class fields:

创建两个类字段:

Handler mHtHandler;
Handler mUiHandler;

and try this:

试试这个:

HandlerThread ht = new HandlerThread("MySuperAwsomeHandlerThread");
ht.start();
Callback callback = new Callback() {
    @Override
    public boolean handleMessage(Message msg) {
        if (msg.what == 0) {
            Log.d(TAG, "got a meaasage in " + Thread.currentThread() + ", now sleeping... ");
            try {
                Thread.sleep(2000);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
            Log.d(TAG, "woke up, notifying ui thread...");
            mUiHandler.sendEmptyMessage(1);
        } else
        if (msg.what == 1) {
            Log.d(TAG, "got a notification in " + Thread.currentThread());
        }
        return false;
    }
};
mHtHandler = new Handler(ht.getLooper(), callback);
mUiHandler = new Handler(callback);
mHtHandler.sendEmptyMessageDelayed(0, 3000);

You can of course get rid of Callbackinterface and create two Handlers with overridden handleMessagemethod...

您当然可以摆脱Callback接口并使用重写的handleMessage方法创建两个处理程序...

回答by Larry Schiefer

The issue you are seeing is because your outer class is using a private mHandler field and so does your HandlerThread. The outer class' field is not initialized. You don't need the inner mHandler. The outer class can crate a handler from the looper you grab right after calling start().

您看到的问题是因为您的外部类使用了私有 mHandler 字段,您的 HandlerThread 也是如此。外部类的字段未初始化。您不需要内部 mHandler。外部类可以在调用 start() 后立即从您抓取的 Looper 中创建处理程序。