java JUnit 3 - 数组包含给定元素
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JUnit 3 - Array contains a given element
提问by Tiago Veloso
I am trying to assert that a given array contains at least one instance of a given element. Is there an assert method that already does this? If so which one?
我试图断言给定数组至少包含给定元素的一个实例。是否有一个断言方法已经做到了这一点？如果有，是哪一个？
I am using Java6 and JUnit3.
我正在使用 Java6 和 JUnit3。
采纳答案by highlycaffeinated
Not a built-in assert, no. You'd need to use assertTrue()and check the array yourself using something like Arrays.binarySearch(), ArrayUtils.contains(), or your own method.
不是内置断言，不是。你需要使用assertTrue()，并检查使用类似自己阵列Arrays.binarySearch()，ArrayUtils.contains()或你自己的方法。
回答by Kevin Bowersox
You can cast the array to a list:
您可以将数组转换为列表：
assertTrue(Arrays.asList(yourArray).contains(yourElement));
回答by bheussler
assertThat(Arrays.asList(yourArray), hasItem(yourElement));
This will give you fine-grained information in the event of a test failure. It will print out your element and the collection it's looking in.
如果测试失败，这将为您提供细粒度的信息。它会打印出你的元素和它正在查找的集合。
回答by yoAlex5
You can try containsInAnyOrder
你可以试试 containsInAnyOrder
assertThat(actual, containsInAnyOrder(expected));
