javascript 用逗号分割字符串，但忽略引号内的逗号
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Split string by comma, but ignore commas inside quotes
提问by ?ime Vidas
Example string:
示例字符串：
"Foo","Bar, baz","Lorem","Ipsum"
Here we have 4values in quotes separated by commas.
这里我们有4 个用逗号分隔的引号值。
When I do this:
当我这样做时：
str.split(',').forEach(…
than that will also split the value "Bar, baz"which I don't want. Is it possible to ignore commas inside quotes with a regular expression?
比这也将分裂"Bar, baz"我不想要的价值。是否可以使用正则表达式忽略引号内的逗号？
回答by hwnd
One way would be using a Positive Lookaheadassertion here.
一种方法是在此处使用Positive Lookahead断言。
var str = '"Foo","Bar, baz","Lorem","Ipsum"',
res = str.split(/,(?=(?:(?:[^"]*"){2})*[^"]*$)/);
console.log(res); // [ '"Foo"', '"Bar, baz"', '"Lorem"', '"Ipsum"' ]
Regular expression:
正则表达式：
, ','
(?= look ahead to see if there is:
(?: group, but do not capture (0 or more times):
(?: group, but do not capture (2 times):
[^"]* any character except: '"' (0 or more times)
" '"'
){2} end of grouping
)* end of grouping
[^"]* any character except: '"' (0 or more times)
$ before an optional \n, and the end of the string
) end of look-ahead
Or a Negative Lookahead
或者一个负面的前瞻
var str = '"Foo","Bar, baz","Lorem","Ipsum"',
res = str.split(/,(?![^"]*"(?:(?:[^"]*"){2})*[^"]*$)/);
console.log(res); // [ '"Foo"', '"Bar, baz"', '"Lorem"', '"Ipsum"' ]
