string 在字符后获取字符串
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Get string after character
提问by user788171
I have a string that looks like this:
我有一个看起来像这样的字符串：
GenFiltEff=7.092200e-01
Using bash, I would like to just get the number after the =character. Is there a way to do this?
使用 bash，我只想获取=字符后的数字。有没有办法做到这一点？
回答by chepner
Use parameter expansion, if the value is already stored in a variable.
如果值已存储在变量中，则使用参数扩展。
$ str="GenFiltEff=7.092200e-01"
$ value=${str#*=}
Or use read
或使用 read
$ IFS="=" read name value <<< "GenFiltEff=7.092200e-01"
Either way,
无论哪种方式，
$ echo $value
7.092200e-01
回答by Tuxdude
For the text after the first =and before the next =
对于第一个之后=和下一个之前的文本=
cut -d "=" -f2 <<< "$your_str"
or
或者
sed -e 's#.*=\(\)##' <<< "$your_str"
For all text after the first =regardless of if there are multiple =
对于第一个之后的所有文本，=无论是否有多个=
cut -d "=" -f2- <<< "$your_str"
回答by Greg Guida
echo "GenFiltEff=7.092200e-01" | cut -d "=" -f2
回答by jman
This should work:
这应该有效：
your_str='GenFiltEff=7.092200e-01'
echo $your_str | cut -d "=" -f2
回答by Explosion Pills
${word:$(expr index "$word" "="):1}
that gets the 7. Assuming you mean the entire rest of the string, just leave off the :1.
得到7. 假设您的意思是字符串的其余部分，只需去掉:1.
