python 确定字节顺序的最 Pythonic 方法是什么？
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What's the most Pythonic way of determining endianness?
提问by Major Major
I'm trying to find the best way of working out whether the machine my code is running on is big-endian or little-endian. I have a solution that works (although I haven't tested it on a big-endian machine) but it seems a bit clunky:
我试图找到确定运行我的代码的机器是大端还是小端的最佳方法。我有一个有效的解决方案（虽然我没有在大端机器上测试过它）但它似乎有点笨拙：
import struct
little_endian = (struct.pack('@h', 1) == struct.pack('<h', 1))
This is just comparing a 'native' two-byte pack to a little-endian pack. Is there a prettier way?
这只是将“本机”两字节包与小端包进行比较。有没有更漂亮的方法？
回答by Scott Griffiths
The answer is in the sys module:
答案在sys 模块中：
>>> import sys
>>> sys.byteorder
'little'
Of course depending on your machine it may return 'big'. Your method should certainly work too though.
当然，根据您的机器，它可能会返回'big'。你的方法当然也应该有效。
