Python Django 得到了一个意外的关键字参数“id”
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Django got an unexpected keyword argument 'id'
提问by Ula
I'm trying to create a phonebook in Django. My urls.py:
我正在尝试在 Django 中创建一个电话簿。我的 urls.py：
urlpatterns = [
url(r'^$', views.people_list, name='people_list'),
url(r'^(?P<id>\d)/$', views.person_detail, name='person_detail'),
]
views.py:
视图.py：
def people_list(request):
people = Person.objects.all()
return render(request, 'phonebook/person/list.html', {'people': people})
def person_detail(request, person):
person = get_object_or_404(Person, id=person)
return render(request, 'phonebook/person/detail.html', {'person': person})
from models.py:
来自models.py：
def get_absolute_url(self):
return reverse('phonebook:person_detail', args=[self.id])
and list.html:
和列表.html：
{% block content %}
<h1>Phonebook</h1>
{% for person in people %}
<h2>
<a href="{{ person.get_absolute_url }}">
{{ person.name }} {{ person.last_name }}
</a>
</h2>
<p class="where">
{{ person.department }}, {{ person.facility }}
</p>
{{ person.phone1 }}<br>
{% endfor %}
{% endblock %}
The index looks ok but when I try click on links to get person_detail site I get this message:
索引看起来不错，但是当我尝试单击链接以获取 person_detail 站点时，我收到以下消息：
TypeError at /phonebook/4/ person_detail() got an unexpected keyword argument 'id' Request Method: GET Request URL: http://127.0.0.1:8000/phonebook/4/Django Version: 1.9.6 Exception Type: TypeError Exception Value: person_detail() got an unexpected keyword argument 'id'
TypeError at /phonebook/4/ person_detail() 得到了一个意外的关键字参数 'id' 请求方法：GET 请求 URL：http: //127.0.0.1:8000/phonebook/4/ Django 版本：1.9.6 异常类型：TypeError 异常值：person_detail() 得到了一个意外的关键字参数“id”
I have and 'id' argument in urls.py and in function to get_absolute_url. I don't understand what's wrong.
我在 urls.py 和 get_absolute_url 函数中有和 'id' 参数。我不明白出了什么问题。
回答by Klaus D.
Your parameter ?P<id>in the URL mapping has to match the arguments in the view def person_detail(request, person):
您的参数?P<id>中的URL映射必须在视图中匹配的参数def person_detail(request, person):
They should both be idor both person.
它们都应该是id或两者都是person。
回答by alecxe
You should fix the view and use the idargument name instead of person:
您应该修复视图并使用id参数名称而不是person：
def person_detail(request, id):
