在 Bash 中解析 SNMP 输出
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Parse SNMP output in Bash
提问by Kareem Hamed
I need to process the text output from the below command:
我需要处理以下命令的文本输出：
snmpwalk -v2c -c community 192.168.122.15 .1.3.6.1.4.1.14823.2.2.1.4.1.2.1.39
The Original output is:
原始输出是：
SNMPv2-SMI::enterprises.14823.2.2.1.4.1.2.1.39.252.200.151.233.54.69.197.39.5.77 = STRING: "Android"
SNMPv2-SMI::enterprises.14823.2.2.1.4.1.2.1.39.252.200.151.233.54.69.197.39.5.77 = STRING: "Android"
I need the output to look like
我需要输出看起来像
197.39.5.77="Android"
197.39.5.77is the last four digits before the =sign.
197.39.5.77是=符号前的最后四位数字。
回答by tripleee
If the prefix is completely static, just remove it.
如果前缀是完全静态的，只需将其删除。
result=$(snmpwalk -v2c -c community 192.168.122.15 .1.3.6.1.4.1.14823.2.2.1.4.1.2.1.39)
result=${result#'SNMPv2-SMI::enterprises.14823.2.2.1.4.1.2.1.39.252.200.151.233.54.69.'}
echo "${result/ = STRING: /}"
Or you could do
或者你可以做
oldIFS=$IFS
IFS=' .'
set $($(snmpwalk -v2c -c community 192.168.122.15 .1.3.6.1.4.1.14823.2.2.1.4.1.2.1.39)
IFS=$oldIFS
shift 16
result="...="
The numeric argument to shiftand the ${var/str/subst}construct are Bashisms.
shift和${var/str/subst}构造的数字参数是 Bashisms。
回答by jxh
With sed:
与sed：
snmpwalk -v2c -c community 192.168.122.15 .1.3.6.1.4.1.14823.2.2.1.4.1.2.1.39 \
| sed -e 's/.*\.\([0-9]\+\(\.[0-9]\+\)\{3\}\).*\(".*"\)/=/'
Or with bashproper:
或bash适当的：
snmpwalk -v2c -c community 192.168.122.15 .1.3.6.1.4.1.14823.2.2.1.4.1.2.1.39 \
| while read a b c; do echo ${a#${a%*.*.*.*.*}.}=\"${c#*\"}; done
回答by dogbane
Pipe through sedas shown below:
管道sed如下图所示：
$ snmpwalk -v2c -c community 192.168.122.15 .1.3.6.1.4.1.14823.2.2.1.4.1.2.1.39 | sed -r 's/.*\.([0-9]+\.[0-9]+\.[0-9]+\.[0-9]+) = .*: (.*)/=/g'
197.39.5.77="Android"
回答by Bentoy13
Try grep -Eo '(\.[0-9]{1,3}){4}\s*=.*$' | sed -r 'sed -r 's/\s*=[^:]+:/=/;s/^\.//'
尝试 grep -Eo '(\.[0-9]{1,3}){4}\s*=.*$' | sed -r 'sed -r 's/\s*=[^:]+:/=/;s/^\.//'
First part is to isolate the end of the line with a good address followed with =; the second part with sederases any string between =and :, and erases also the first dot before IPv4 address. For compactness, grepis searching for 4 times a dot followed with at most 3 digits.
第一部分是用一个好的地址来隔离行尾，然后是=; 第二部分 withsed擦除=和之间的任何字符串:，并擦除 IPv4 地址之前的第一个点。为了紧凑，grep正在搜索 4 次一个点，后跟最多 3 位数字。
