bash 将数字添加到文件中每一行的开头
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Add numbers to the beginning of every line in a file
提问by Village
How can I add numbers to the beginning of every line in a file?
如何在文件中每一行的开头添加数字？
E.g.:
例如：
This is the text from the file.
Becomes:
变成：
000000001 This is 000000002 the text 000000003 from the file.
采纳答案by Raymond Hettinger
AWK's printf, NRand $0make it easy to have precise and flexible control over the formatting:
AWK 的printf，NR并$0可以轻松地对格式进行精确和灵活的控制：
~ $ awk '{printf("%010d %s\n", NR, nl --number-format=rz --number-width=9 foobar
)}' example.txt
0000000001 This is
0000000002 the text
0000000003 from the file.
回答by tamasgal
Don't use cat or any other tool which is not designed to do that. Use the program:
不要使用 cat 或任何其他不是为此设计的工具。使用程序：
nl - number lines of files
nl - 文件行数
Example:
例子：
$ nl -nrz -w9 /etc/passwd
000000001 root:x:0:0:root:/root:/bin/bash
000000002 daemon:x:1:1:daemon:/usr/sbin:/bin/sh
000000003 bin:x:2:2:bin:/bin:/bin/sh
...
Because nl is made for it ;-)
因为 nl 是为它而生的 ;-)
回答by sarnold
You're looking for the nl(1)command:
您正在寻找以下nl(1)命令：
awk '{print NR,perl -pe 'printf "%09u ", $.' -- example.txt
}' file
-w9asks for numbers nine digits long; -nrzasks for the numbers to be formatted right-justified with zero padding.
-w9要求九位数的数字；-nrz要求数字以零填充右对齐。
回答by duskwuff -inactive-
cat -n thefilewill do the job, albeit with the numbers in a slightly different format.
cat -n thefile将完成这项工作，尽管数字格式略有不同。
回答by egorulz
Easiest, simplest option is
最简单、最简单的选择是
#!/bin/bash
counter=0
filename=
while read -r line
do
printf "%010d %s" $counter $line
let counter=$counter+1
done < "$filename"
See comment above on why nl isn't really the best option.
请参阅上面关于为什么 nl 不是最佳选择的评论。
回答by Peter John Acklam
回答by slashdottir
Here's a bash script that will do this also:
这是一个也可以执行此操作的 bash 脚本：
##代码##