jQuery AJAX 调用中是否有类似于“终于”的东西？
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Is there any analog to a 'finally' in jQuery AJAX calls?
提问by Oliver Watkins
Is there a Java 'finally' analogue in jQuery AJAX calls? I have this code here. In my alwaysI throw an exception, however I ALWAYS want it to go to the then()method.
jQuery AJAX 调用中是否有 Java 'finally' 类似物？我这里有这个代码。我总是抛出一个异常，但是我总是希望它转到then()方法。
call.xmlHttpReq = $.ajax({
url : url,
dataType : 'json',
type : 'GET'
}).always(function(processedDataOrXHRWrapper, textStatus, xhrWrapperOrErrorThrown) {
throw "something";
}).then(function() {
alert("i want to always run no matter what");
});
I have tried to use done(), complete(), and the another always(), but nothing seems to work.
我尝试使用done()、complete()和另一个always()，但似乎没有任何效果。
Here is JSFiddle :
这是 JSFiddle ：
回答by Rafael Gomes Francisco
See this example:
看这个例子：
$.ajax({
type: "GET",
dataType: dataType,
contentType: contentType,
async: TRUE,
url: $('html form:nth-child(1)').attr('action') + "?" $('html form:nth-child(1)').serialize(),
success: function(data) {
console.log("FUNFOU!");
},
error: function(data) {
console.log("N?O FUNFOU!");
},
complete: function(data) {
console.log("SEMPRE FUNFA!");
//A function to be called when the request finishes
// (after success and error callbacks are executed).
}
});
For more informations: http://api.jquery.com/jquery.ajax/
回答by jrummell
.always()should work. See the The jqXHR Objectsection at http://api.jquery.com/jQuery.ajax/.
.always()应该管用。请参阅http://api.jquery.com/jQuery.ajax/ 上的 jqXHR 对象部分。
jqXHR.always(function(data|jqXHR, textStatus, jqXHR|errorThrown) { }); An alternative construct to the complete callback option, the .always() method replaces the deprecated .complete() method.
In response to a successful request, the function's arguments are the same as those of .done(): data, textStatus, and the jqXHR object. For failed requests the arguments are the same as those of .fail(): the jqXHR object, textStatus, and errorThrown. Refer to deferred.always() for implementation details.
jqXHR.always(function(data|jqXHR, textStatus, jqXHR|errorThrown) { }); 完整回调选项的替代构造， .always() 方法替换了已弃用的 .complete() 方法。
为了响应成功的请求，该函数的参数与 .done() 的参数相同：data、textStatus 和 jqXHR 对象。对于失败的请求，参数与 .fail() 的参数相同：jqXHR 对象、textStatus 和 errorThrown。有关实现细节，请参阅 deferred.always()。
回答by David McMullin
The below suggestions will not work in jQuery, because jQuery's promise implementation does not handle errors thrown in methods passed to then. I am only leaving them here as an illustration of what could be possible if jQuery was promises/A+ compliant. As Bergi rightly points out, you will have to manually wrap your code in your own try catch block.
下面的建议在 jQuery 中不起作用，因为 jQuery 的 promise 实现不处理传递给 then 的方法中抛出的错误。我把它们留在这里只是为了说明如果 jQuery 是 promises/A+ 兼容的话，可能会发生什么。正如 Bergi 正确指出的那样，您必须手动将代码包装在您自己的 try catch 块中。
call.xmlHttpReq = $.ajax({
url : url,
dataType : 'json',
type : 'GET'
}).then(function(processedDataOrXHRWrapper, textStatus, xhrWrapperOrErrorThrown) {
throw "something";
}).always(function() {
alert("i want to always run no matter what");
});
Although I'm not sure if jquery's promise supports always, an alternative would be to use then (again) and pass the same function as both successHandler and errorHandler, like this :
虽然我不确定 jquery 的承诺是否总是支持，但另一种方法是使用 then（再次）并传递与 successHandler 和 errorHandler 相同的函数，如下所示：
call.xmlHttpReq = $.ajax({
url : url,
dataType : 'json',
type : 'GET'
}).then(function(processedDataOrXHRWrapper, textStatus, xhrWrapperOrErrorThrown) {
throw "something";
}).then(function() {
alert("i want to always run no matter what");
},
function() {
alert("i want to always run no matter what");
});
回答by Jayavardhan Gange
Just a note for those who use jQuery 3.0 and later
给那些使用 jQuery 3.0 及更高版本的人的注意事项
Deprecation Notice: The jqXHR.success(), jqXHR.error(), and jqXHR.complete() callbacks are removed as of jQuery 3.0. You can use jqXHR.done(), jqXHR.fail(), and jqXHR.always() instead.
弃用通知：jqXHR.success()、jqXHR.error() 和 jqXHR.complete() 回调从 jQuery 3.0 开始被移除。您可以改用 jqXHR.done()、jqXHR.fail() 和 jqXHR.always()。
回答by KingRider
There is a bug ajax is dependent on the server, need to check status with "complete" is the best, a kind of "success", "error" and others are not 100% of the PUT, POST and GET ... look at an example
有一个bug ajax是依赖服务器的，需要检查状态用“完成”最好，一种“成功”、“错误”等不是100%的PUT、POST和GET……看看举个例子
$.ajax({
url: '/api/v2/tickets/123456.json',
....
....
....
complete: function(data) {
if (data.statusText == "success") {
console.log("Sent successfully");
} else {
console.log("Not Sent");
}
}
});
Sorry bad english! Cheer ;-)
对不起英语不好！加油;-)
回答by sairfan
if you want one code definition for all ajax requests, you can do it like this
如果你想要所有 ajax 请求的一个代码定义，你可以这样做
$(document).ajaxComplete(function () {
console.log('ajax complete on doc');
})
