从 Bash 脚本输出 JSON
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Output JSON from Bash script
提问by Justin
So I have a bashscript which outputs details on servers. The problem is that I need the output to be JSON. What is the best way to go about this? Here is the bash script:
所以我有一个bash脚本可以输出服务器的详细信息。问题是我需要输出为JSON. 解决这个问题的最佳方法是什么？这是 bash 脚本：
# Get hostname
hostname=`hostname -A` 2> /dev/null
# Get distro
distro=`python -c 'import platform ; print platform.linux_distribution()[0] + " " + platform.linux_distribution()[1]'` 2> /dev/null
# Get uptime
if [ -f "/proc/uptime" ]; then
uptime=`cat /proc/uptime`
uptime=${uptime%%.*}
seconds=$(( uptime%60 ))
minutes=$(( uptime/60%60 ))
hours=$(( uptime/60/60%24 ))
days=$(( uptime/60/60/24 ))
uptime="$days days, $hours hours, $minutes minutes, $seconds seconds"
else
uptime=""
fi
echo $hostname
echo $distro
echo $uptime
So the output I want is something like:
所以我想要的输出是这样的：
{"hostname":"server.domain.com", "distro":"CentOS 6.3", "uptime":"5 days, 22 hours, 1 minutes, 41 seconds"}
Thanks.
谢谢。
回答by Steve
If you only need to output a small JSON, use printf:
如果您只需要输出一个小的 JSON，请使用printf：
printf '{"hostname":"%s","distro":"%s","uptime":"%s"}\n' "$hostname" "$distro" "$uptime"
Or if you need to produce a larger JSON, use a heredocas explained by leandro-mora. If you use the here-doc solution, please be sure to upvote his answer:
或者，如果您需要生成更大的 JSON，请使用Leedro-mora解释的heredoc。如果您使用 here-doc 解决方案，请务必支持他的回答：
cat <<EOF > /your/path/myjson.json
{"id" : "$my_id"}
EOF
Some of the more recent distros, have a file called: /etc/lsb-releaseor similar name (cat /etc/*release). Therefore, you could possiblydo away with dependency your on Python:
一些较新的发行版有一个名为:/etc/lsb-release或类似名称 ( cat /etc/*release) 的文件。因此，你可以有可能废除Python的依赖你：
distro=$(awk -F= 'END { print }' /etc/lsb-release)
An aside, you should probably do away with using backticks. They're a bit old fashioned.
顺便说一句，您可能应该取消使用反引号。它们有点老式。
回答by Leandro Mora
I find it much more easy to create the json using cat:
我发现使用cat以下方法创建 json 更容易：
cat <<EOF > /your/path/myjson.json
{"id" : "$my_id"}
EOF
回答by Jimilian
I'm not a bash-ninja at all, but I wrote a solution, that works perfectly for me. So, I decided to share itwith community.
我根本不是 bash-ninja，但我写了一个解决方案，这对我来说非常有效。所以，我决定与社区分享。
First of all, I created a bash script called json.sh
首先，我创建了一个名为的 bash 脚本 json.sh
arr=();
while read x y;
do
arr=("${arr[@]}" $x $y)
done
vars=(${arr[@]})
len=${#arr[@]}
printf "{"
for (( i=0; i<len; i+=2 ))
do
printf "\"${vars[i]}\": ${vars[i+1]}"
if [ $i -lt $((len-2)) ] ; then
printf ", "
fi
done
printf "}"
echo
And now I can easily execute it:
现在我可以轻松地执行它：
$ echo key1 1 key2 2 key3 3 | ./json.sh
{"key1":1, "key2":2, "key3":3}
回答by Daro
@Jimilian script was very helpful for me. I changed it a bit to send data to zabbix auto discovery
@Jimilia 脚本对我很有帮助。我稍微改变了一下，将数据发送到zabbix 自动发现
arr=()
while read x y;
do
arr=("${arr[@]}" $x $y)
done
vars=(${arr[@]})
len=${#arr[@]}
printf "{\n"
printf "\t"data":[\n"
for (( i=0; i<len; i+=2 ))
do
printf "\t{ "{#VAL1}":\"${vars[i]}\",\t"{#VAL2}":\"${vars[i+1]}\" }"
if [ $i -lt $((len-2)) ] ; then
printf ",\n"
fi
done
printf "\n"
printf "\t]\n"
printf "}\n"
echo
Output:
输出：
$ echo "A 1 B 2 C 3 D 4 E 5" | ./testjson.sh
{
data:[
{ {#VAL1}:"A", {#VAL2}:"1" },
{ {#VAL1}:"B", {#VAL2}:"2" },
{ {#VAL1}:"C", {#VAL2}:"3" },
{ {#VAL1}:"D", {#VAL2}:"4" },
{ {#VAL1}:"E", {#VAL2}:"5" }
]
}
回答by Fedir RYKHTIK
I wrote a tiny program in Go, json_encode. It works pretty good for such cases:
我用 Go 写了一个小程序json_encode。对于这种情况，它非常有效：
$ ./getDistro.sh | json_encode
["my.dev","Ubuntu 17.10","4 days, 2 hours, 21 minutes, 17 seconds"]
回答by Navaganesh R
data=$(echo " BUILD_NUMBER : ${BUILD_NUMBER} , BUILD_ID : ${BUILD_ID} , JOB_NAME : ${JOB_NAME} " | sed 's/ /"/g')
output => data="BUILD_NUMBER":"29","BUILD_ID":"29","JOB_NAME":"OSM_LOG_ANA"
