如何在Linux上按名称对某个目录中的文件进行排序
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How to sort files in some directory by the names on Linux
提问by JavaMobile
I use opendir()and readdir()to display the file names in a directory. But they are disordered. How can I sort them? The language is C.
我使用opendir()和readdir()来显示目录中的文件名。但它们是无序的。我怎样才能对它们进行排序？语言是C。
采纳答案by unwind
The idiomatic way to sort something in C is to use the qsort()function. For this to work, it's best if you can arrange to have all the file names collected into an array of pointers, and then you sort the array.
在 C 中对某些内容进行排序的惯用方法是使用该qsort()函数。为此，最好可以安排将所有文件名收集到一个指针数组中，然后对数组进行排序。
This is not too hard, but it does require either a bit of dynamic-array management, or that you introduce static limits on things (maximum length of filenames, maximum number of files).
这并不太难，但它确实需要一些动态数组管理，或者您对事物引入静态限制（文件名的最大长度，文件的最大数量）。
回答by hipe
Maybe you could use scandir() instead of opendir and readdir?
也许您可以使用 scandir() 而不是 opendir 和 readdir？
#include <stdio.h>
#include <stdlib.h>
#include <dirent.h>
int
main(void)
{
struct dirent **namelist;
int n;
n = scandir(".", &namelist, 0, alphasort);
if (n < 0)
perror("scandir");
else {
while (n--) {
printf("%s\n", namelist[n]->d_name);
free(namelist[n]);
}
free(namelist);
}
}
回答by Christoffer Hammarstr?m
You have to dynamically construct a data structure containing the filenames and make sure it is sorted.
您必须动态构建包含文件名的数据结构并确保对其进行排序。
You could build an array or linked list with the names, and then sort that, but my preference is to sort the values on insertion by inserting into a binary tree.
您可以使用名称构建一个数组或链表，然后对其进行排序，但我的偏好是通过插入二叉树来对插入时的值进行排序。
