javascript 有没有办法只获取顶部元素的innerText（并忽略子元素的innerText）？

Is there a way to get innerText of only the top element (and ignore the child element's innerText)?

提问by ivymike

Is there a way to get innerText of only the top element (and ignore the child element's innerText) ?

有没有办法只获取顶部元素的innerText（并忽略子元素的innerText）？

Example:

例子：

<div> 
   top node text 
   <div> child node text </div>
</div>

How to get the "top node text" while ignoring "child node text" ? innerText property of top div seem to return concatenation of both inner , top text.

如何在忽略“子节点文本”的同时获取“顶部节点文本”？top div 的innerText 属性似乎返回inner 和top 文本的串联。

回答by Tim Down

Just iterate over the child nodes and concatenate text nodes:

只需遍历子节点并连接文本节点：

var el = document.getElementById("your_element_id"),
    child = el.firstChild,
    texts = [];

while (child) {
    if (child.nodeType == 3) {
        texts.push(child.data);
    }
    child = child.nextSibling;
}

var text = texts.join("");

回答by Rob W

1. Clone the element.
2. Loop through all child nodes (backwards, to avoid conflicts):
   If the element has a tagNameattribute, then it's an element: Remove the node.
3. Use innerTextto get the textual contents (with fallback to textContent, when innerTextis not supported).

1. 克隆元素。
2. 循环遍历所有子节点（向后，以避免冲突）：
   如果元素具有tagName属性，则它是一个元素：删除节点。
3. 使用innerText来获取文本内容（回退到textContent时innerText不支持）。

Code:

代码：

var elem = document.getElementById('theelement');
elem = elem.cloneNode(true);
for (var i=elem.childNodes.length-1; i>=0; i--) {
    if (elem.childNodes[i].tagName) elem.removeChild(elem.childNodes[i]);
}
var innerText = elem['innerText' in elem ? 'innerText' : 'textContent'];

回答by sensor

This will work in your example: document.getElementById("item").firstChild.nodeValue;

这将适用于您的示例： document.getElementById("item").firstChild.nodeValue;

Note: Keep in mind that this will work if you know you are dealing with that specific HTML. If your HTML can change, for example to:

注意：请记住，如果您知道您正在处理特定的 HTML，这将起作用。如果您的 HTML 可以更改，例如：

<div> 
    <div class="item"> child node text </div>
    top node text 
</div>

then you should use the more generic solution by @Tim Down

那么你应该使用@Tim Down 提供的更通用的解决方案

---

---

Here is working code snippet:

这是工作代码片段：

window.onload = function() {
   var text = document.getElementById("item").firstChild.nodeValue;
   document.getElementById("result").innerText = text.trim();
};

#result {
  border: 1px solid red;
}

<div id="item">
  top node text 
   <div> child node text </div>
</div>



<strong>Result:</strong> <div id="result"></div>

回答by ehsaneha

function getDirectInnerText(element) {
  var childNodes = element.childNodes;
  result = '';

  for (var i = 0; i < childNodes.length; i++) {
    if(childNodes[i].nodeType == 3) {
      result += childNodes[i].data;
    }
  }

  return result;
}

element = document.querySelector("div#element");
console.log(getDirectInnerText(element))

<div id="element"> 
   top node text 
   <div> child node text </div>
</div>

回答by johnwcb

If you don't want to ignore the child element's inner text, use the following function:

如果不想忽略子元素的内部文本，请使用以下函数：

function getInnerText(el) {
    var x = [];
    var child = el.firstChild;
    while (child) {
        if (child.nodeType == 3) {
            x.push(child.nodeValue);
        }
        else if (child.nodeType == 1) {
            var ii = getInnerText(child);
            if (ii.length > 0) x.push(ii);
        }
        child = child.nextSibling;
    }
    return x.join(" ");
}