检查文本框是否在 JavaScript 中禁用或启用

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时间:2020-08-23 03:56:32  来源:igfitidea点击:

Check if textbox disabled or enabled in JavaScript

javascript

提问by alvinski

How do I check if a textbox is disabled or enabled in JavaScript? I just want to know if a textbox is enable or disabled on button click. If the textbox is disabled I want to alert the user with the message "disabled" and if it is enable, the alert message will be "enabled".

如何检查文本框是否在 JavaScript 中被禁用或启用?我只想知道在单击按钮时启用还是禁用文本框。如果文本框被禁用,我想用“禁用”消息提醒用户,如果启用,警报消息将“启用”。

<script>
 function CheckTextbox(){

    if(textbox1 is disabled){ //here
      alert("disabled");
    }else{
      alert("enable");
    }

   if(textbox2 is disabled){ //here
      alert("disabled");
   }else{
      alert("enable");
   }
}
</script>

<input type="text" id="textbox1" disabled="disabled">
<input type="text" id="textbox2">
<input type="button" onclick="CheckTextbox();">

回答by

Try using document.getElementById('textbox1').disabled

尝试使用 document.getElementById('textbox1').disabled

function CheckTextbox() {
  var id;
  for (var i = 1; 2 >= i; i++) {
    id = 'textbox' + i;
    console.log(id, 'is disabled ?', document.getElementById(id).disabled);
  }
}
<input type="text" id="textbox1" disabled="disabled">
<input type="text" id="textbox2">
<input type="button" onclick="CheckTextbox();" value='Check'>

回答by Abdullah Al Noman

function CheckTextbox() {
   var textbox = document.getElementById('textbox1');

   if (textbox.disabled) {
      // If disabled, do this 
       alert("disabled");
    } else {
       // Enter code here
        alert("Not disabled");
     }
}
<input type="text" id="textbox1" disabled="disabled">
<input type="button" onclick="CheckTextbox();">

回答by Lokesh Kumar

function CheckTextbox(){

    if(document.getElementById("textbox1").disabled){ //here
       alert("disabled");
    }else{
      alert("enabled");
     }


   if(document.getElementById("textbox2").disabled) { //here
      alert("disabled");
   }else{
      alert("enabled");
   }

}

回答by cakan

function CheckTextbox(){

    if(document.getElementById("textbox1").disabled == true){ //here
        alert("disabled");
    }else{
        alert("enable");
    }

    if(document.getElementById("textbox2").disabled == true){ //here
        alert("disabled");
    }else{
        alert("enable");
    }

}

回答by Zvi Redler

<script>
function CheckTextbox(){
    var textbox=document.getElementById('textbox1');

if(textbox.disabled)

   {alert("disabled"); }

else{alert("enable");}

var textbox2=document.getElementById('textbox2');
   if(textbox2.disabled){ //here
       alert("disabled");
    }else{
       alert("enable");
    }
}
</script>

<input type="text" id="textbox1" disabled="disabled">
<input type="text" id="textbox2">
<input type="button" onclick="CheckTextbox();">

回答by syms

<input type="text" id="textbox1" disabled="disabled">
<input type="text" id="textbox2">
<input type="button" onclick="CheckTextbox();">
<script>
 (function CheckTextbox(){
    if(document.getElementById('textbox1').disabled){
     alert("disabled");
    }else{
     alert("enable");
   }

   if(document.getElementById('textbox2').disabled){ 
    alert("disabled");
   }else{
    alert("enable");
   }
})()
</script>

回答by Adrian Oprea

As far as I can see all responses are deeply tied to #textbox1which is bad as your HTML may not always look like that, and states might change. Secondly, I'd use DOM level 2 event handlers instead of DOM level 0.

据我所知,所有响应都与#textbox1哪个不好相关,因为您的 HTML 可能并不总是这样,并且状态可能会改变。其次,我会使用 DOM 级别 2 事件处理程序而不是 DOM 级别 0。

Check the BIN below:

检查下面的 BIN:

http://jsbin.com/hecoyemano/2/

http://jsbin.com/hecoyemano/2/