xml 在 XSLT v1.0 中使用结尾
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Use ends with in XSLT v1.0
提问by user1582320
I am trying to edit a current XSLT. The functionality I want is when the value of "//code_no" ends with 01 I want to edit the current city location. Currently this functionality does not exist. I have tried using string and substring but it gives me an error saying ends with functionality does not exist. Please help
我正在尝试编辑当前的 XSLT。我想要的功能是当“//code_no”的值以 01 结尾时，我想编辑当前城市位置。目前此功能不存在。我试过使用字符串和子字符串，但它给了我一个错误，说以功能结束不存在。请帮忙
The value coming from the xml is
来自 xml 的值是
<code_no>
1870410001
</code_no>
in the xsl, I want to print this when the value ends with 01.
在 xsl 中，我想在值以 01 结尾时打印它。
<td align="left" width="33%"><SPAN style="font-size: 12pt; font-family: Arial;">
<a> <b><u><xsl:value-of select="//city"/>, <xsl:value-of select="//state"/>
</u></b></a></SPAN></td>
回答by Dimitre Novatchev
The XPath 1.0 equivalent of (the XPath 2.0) expression:
XPath 1.0 等效于（XPath 2.0）表达式：
ends-with($s, $t)
is:
是：
$t = substring($s, string-length($s) - string-length($t) +1)
You need just to substitute $sand $tin the last XPath expressionwith, respectively, the string to be tested, and the ending to be tested.
你只需要以替代$s和$t在过去的XPath表达式与分别要测试的字符串，并且要测试的结束。
Here is a complete example:
这是一个完整的示例：
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="x|y">
<xsl:value-of select="name()"/> ends-with '_01': <xsl:value-of select=
"'_01' = substring(., string-length() - 2)"/>
=============
</xsl:template>
</xsl:stylesheet>
when this transformation is applied on the following XML document(none was provided in the question!!!):
当此转换应用于以下 XML 文档时（问题中没有提供！！！）：
<t>
<x>abcd_01</x>
<y>abcd_11</y>
</t>
the wanted, correct result is produced:
产生了想要的、正确的结果：
x ends-with '_01': true
=============
y ends-with '_01': false
=============
回答by Wayne
回答by Jyotsna Sonawane
I used
我用了
contains($string, $part) and normalize-space(substring-after($string, $part)) = ''
Where
在哪里
we are checking if $string ends with $part
我们正在检查 $string 是否以 $part 结尾
回答by VladoS
In special cases, if you know that some character can not be contained in tag for example § you can do this:
在特殊情况下，如果您知道某些字符不能包含在标签中，例如 § 您可以这样做：
<xsl:if test="contains(concat(code_no,'§'),'01§')">
<td align="left" width="33%"><SPAN style="font-size: 12pt; font-family: Arial;">
<a> <b><u><xsl:value-of select="//city"/>, <xsl:value-of select="//state"/>
</u></b></a></SPAN></td>
</xsl:if>
回答by CodeManX
Not exactly ends with, but nicer look than the substring-solution and still suitable for certain situations:
不完全以 结尾，但比子字符串解决方案更好看，并且仍然适用于某些情况：
<xsl:template match="*[contains(name(), 'substr')]"/>
