pandas 熊猫：如何使用 _iLocIndexer？
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pandas: How to work with _iLocIndexer?
提问by user650654
>>> import pandas as pd
>>> pd.__version__
'0.16.1'
>>> s1 = pd.Series([1, 3, 5], index=list('abc'))
>>> s1.iloc(0)
<pandas.core.indexing._iLocIndexer object at 0x10ca3f690>
I expected the integer 1 to be returned for s1.iloc(0), but got an _iLocIndexerobject instead. What can I do with this object? How do I work with it?
我希望为 返回整数 1 s1.iloc(0)，但得到了一个_iLocIndexer对象。我可以用这个对象做什么？我如何使用它？
回答by user650654
The solution, due to @JohnE, is to use square brackets [0]instead of (0)with iloc.
由于@JohnE，解决方案是使用方括号[0]而不是(0)with iloc。
Some more info after digging through some pandas code.
挖掘一些Pandas代码后，还有更多信息。
s1.ilocmakes iloclook like a method. But it is an attribute and the value of the attribute is _iLocIndexer. _iLocIndexeris callable with arguments and it returns a copy of itself ignoring any args or kwargs (see pandas.core.indexing._NDFrameIndexer.callin pandas code). This is why s1.iloc(0)is a valid call.
s1.iloc让iloc看起来像一种方法。但它是一个属性，该属性的值为_iLocIndexer。 _iLocIndexer是可调用带参数和返回（见pandas.core.indexing._NDFrameIndexer，其自身的副本忽略任何ARGS或kwargs呼叫在大Pandas代码）。这就是s1.iloc(0)有效调用的原因。
When s1.iloc[0]is called with square brackets, an _iLocIndexeris instantiated and the call to []operator results in a call to the iLocIndexer's `getitem' method.
当s1.iloc[0]用方括号调用时， an_iLocIndexer被实例化并且对[]operator 的调用导致对iLocIndexer“getitem”方法的调用。
The same is true for the other indexers - loc, ix, atand iat. These indexers are installed using setattrin class method pandas.core.generic.NDFrame._create_indexer.
这同样适用于其他索引真的- ，，和。这些索引器是使用类方法 pandas.core.generic.NDFrame._create_indexer安装的。locixatiatsetattr
