.net C#在字符串中添加一个字符

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时间:2020-09-03 14:47:55  来源:igfitidea点击:

C# adding a character in a string

.netvisual-studio-2008c#-3.0

提问by pablosal

I know I can append to a string but I want to be able to add a specific character after every 5 characters within the string

我知道我可以附加到一个字符串,但我希望能够在字符串中的每 5 个字符后添加一个特定字符

from this string alpha = abcdefghijklmnopqrstuvwxyz

从这个字符串 alpha = abcdefghijklmnopqrstuvwxyz

to this string alpha = abcde-fghij-klmno-pqrst-uvwxy-z

到这个字符串 alpha = abcde-fghij-klmno-pqrst-uvwxy-z

回答by Preet Sangha

Remember a string is immutable so you will need to create a new string.

请记住,字符串是不可变的,因此您需要创建一个新字符串。

Strings are IEnumerable so you should be able to run a for loop over it

字符串是 IEnumerable 所以你应该能够在它上面运行一个 for 循环

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            string alpha = "abcdefghijklmnopqrstuvwxyz";
            var builder = new StringBuilder();
            int count = 0;
            foreach (var c in alpha)
            {
                builder.Append(c);
                if ((++count % 5) == 0)
                {
                    builder.Append('-');
                }
            }
            Console.WriteLine("Before: {0}", alpha);
            alpha = builder.ToString();
            Console.WriteLine("After: {0}", alpha);
        }
    }
}

Produces this:

产生这个:

Before: abcdefghijklmnopqrstuvwxyz
After: abcde-fghij-klmno-pqrst-uvwxy-z

回答by NocFenix

I had to do something similar, trying to convert a string of numbers into a timespan by adding in :and .. Basically I was taking 235959999 and needing to convert it to 23:59:59.999. For me it was easy because I knew where I needed to "insert" said characters.

我不得不做类似的事情,尝试通过添加:和将一串数字转换为时间跨度.。基本上我正在服用 235959999 并需要将其转换为 23:59:59.999。对我来说这很容易,因为我知道我需要在哪里“插入”所述字符。

ts = ts.Insert(6,".");
ts = ts.Insert(4,":");
ts = ts.Insert(2,":");

Basically reassigning ts to itself with the inserted character. I worked my way from the back to front, because I was lazy and didn't want to do additional math for the other inserted characters.

基本上是用插入的字符将 ts 重新分配给自己。我从后到前工作,因为我很懒,不想为其他插入的字符做额外的数学运算。

You could try something similar by doing:

您可以通过执行以下操作来尝试类似的操作:

alpha = alpha.Insert(5,"-");
alpha = alpha.Insert(11,"-"); //add 1 to account for 1 -
alpha = alpha.Insert(17,"-"); //add 2 to account for 2 -
...

回答by danijels

Here is my solution, without overdoing it.

这是我的解决方案,不过分。

    private static string AppendAtPosition(string baseString, int position, string character)
    {
        var sb = new StringBuilder(baseString);
        for (int i = position; i < sb.Length; i += (position + character.Length))
            sb.Insert(i, character);
        return sb.ToString();
    }


    Console.WriteLine(AppendAtPosition("abcdefghijklmnopqrstuvwxyz", 5, "-"));

回答by Andrei Bularca

string alpha = "abcdefghijklmnopqrstuvwxyz";
string newAlpha = "";
for (int i = 5; i < alpha.Length; i += 6)
{
  newAlpha = alpha.Insert(i, "-");
  alpha = newAlpha;
}

回答by Raj

Inserting Space in emailId field after every 8 characters

每 8 个字符后在 emailId 字段中插入空格

public string BreakEmailId(string emailId) {
    string returnVal = string.Empty;
    if (emailId.Length > 8) {           
        for (int i = 0; i < emailId.Length; i += 8) {
            returnVal += emailId.Substring(i, 8) + " ";
        }
    }

    return returnVal;
}

回答by Eugene Cheverda

You may define this extension method:

你可以定义这个扩展方法:

public static class StringExtenstions
    {
        public static string InsertCharAtDividedPosition(this string str, int count, string character)
        {
            var i = 0;
            while (++i * count + (i - 1) < str.Length)
            {
                str = str.Insert((i * count + (i - 1)), character);
            }
            return str;
        }
    }

And use it like:

并像这样使用它:

var str = "abcdefghijklmnopqrstuvwxyz";
str = str.InsertCharAtDividedPosition(5, "-");

回答by Darth Android

string[] lines = Regex.Split(value, ".{5}");  
string out = "";
foreach (string line in lines)  
{  
    out += "-" + line;
}
out = out.Substring(1);