javascript 如何在 JSF 中打开弹出窗口
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时间：2020-10-27 07:19:41 来源:igfitidea点击:
How can I open a Popup in JSF
提问by NDeveloper
I need to open a Popup window on clicking a button in a xhtml page. I have written something like that:
我需要在单击 xhtml 页面中的按钮时打开一个弹出窗口。我写过这样的东西：
<p:commandButton type="submit" value="Select User" onclick="showGrpMemberSearchPageCalenderLeave()"/>
and the java script is like:
和java脚本是这样的：
function showGrpMemberSearchPageCalenderLeave()
{
window.open('./SearchGroupMembersLeaveCalander.xhtml,resizable=no,
toolbar=no,scrollbars=yes,height=450,width=530,top=145,left=235');
return true;
}
But it just opens the page in the current window, no pop up window is opening.Please suggest.
但它只是在当前窗口打开页面，没有打开弹出窗口。请建议。
回答by Markipe
try this one instead
试试这个
function showGrpMemberSearchPageCalenderLeave() {
window.open('./SearchGroupMembersLeaveCalander.xhtml','mywindow', 'resizable=no,toolbar=no,scrollbars=yes,height=450,width=530,top=145,left=235');
return true;
}
Syntax
句法
window.open(url, windowName, specs);
