烧瓶 Python 按钮
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Flask Python Buttons
提问by dojogeorge
Im trying to create two buttons on a page. Each one I would like to carry out a different python script on the server. So far I have only managed to get/collect one button using
我试图在页面上创建两个按钮。每一个我都想在服务器上执行一个不同的 python 脚本。到目前为止，我只设法使用
def contact():
form = ContactForm()
if request.method == 'POST':
return 'Form posted.'
elif request.method == 'GET':
return render_template('contact.html', form=form)
What would I need to change based on button pressed?
根据按下的按钮，我需要更改什么？
采纳答案by Miguel
Give your two buttons the same name and different values:
为您的两个按钮指定相同的名称和不同的值：
<input type="submit" name="submit_button" value="Do Something">
<input type="submit" name="submit_button" value="Do Something Else">
Then in your Flask view function you can tell which button was used to submit the form:
然后在你的 Flask 视图函数中，你可以知道哪个按钮用于提交表单：
def contact():
if request.method == 'POST':
if request.form['submit_button'] == 'Do Something':
pass # do something
elif request.form['submit_button'] == 'Do Something Else':
pass # do something else
else:
pass # unknown
elif request.method == 'GET':
return render_template('contact.html', form=form)
回答by Pawe? Pogorzelski
Apply (different) name attribute to both buttons like
将（不同的）名称属性应用于两个按钮，例如
<button name="one">
and catch them in request.data.
并在 request.data 中捕获它们。
回答by Alexander.Iljushkin
The appropriate way for doing this:
执行此操作的适当方法：
@app.route('/')
def index():
if form.validate_on_submit():
if 'download' in request.form:
pass # do something
elif 'watch' in request.form:
pass # do something else
Put watchand downloadbuttons into your template:
将watch和download按钮放入您的模板中：
<input type="submit" name="download" value="Download">
<input type="submit" name="watch" value="Watch">
回答by rashid
I handle it in the following way:
我按以下方式处理：
<html>
<body>
<form method="post" action="/">
<input type="submit" value="Encrypt" name="Encrypt"/>
<input type="submit" value="Decrypt" name="Decrypt" />
</div>
</form>
</body>
</html>
Python Code :
蟒蛇代码：
from flask import Flask, render_template, request
app = Flask(__name__)
@app.route("/", methods=['GET', 'POST'])
def index():
print(request.method)
if request.method == 'POST':
if request.form.get('Encrypt') == 'Encrypt':
# pass
print("Encrypted")
elif request.form.get('Decrypt') == 'Decrypt':
# pass # do something else
print("Decrypted")
else:
# pass # unknown
return render_template("index.html")
elif request.method == 'GET':
# return render_template("index.html")
print("No Post Back Call")
return render_template("index.html")
if __name__ == '__main__':
app.run()
回答by poply
In case anyone was still looking and came across this SO post like I did.
万一有人仍在寻找并像我一样看到这篇SO帖子。
<input type="submit" name="open" value="Open">
<input type="submit" name="close" value="Close">
def contact():
if "open" in request.form:
pass
elif "close" in request.form:
pass
return render_template('contact.html')
Simple, concise, and it works. Don't even need to instantiate a form object.
简单，简洁，并且有效。甚至不需要实例化一个表单对象。
回答by slinden
I think this solution is good:
我认为这个解决方案很好：
@app.route('/contact', methods=['GET', 'POST'])
def contact():
form = ContactForm()
if form.validate_on_submit():
if form.submit.data:
pass
elif form.submit2.data:
pass
return render_template('contact.html', form=form)
Form:
形式：
class ContactForm(FlaskForm):
submit = SubmitField('Do this')
submit2 = SubmitField('Do that')
