Java Swing 计时器倒计时
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Java Swing Timer Countdown
提问by BigBigBiggle
I have to make a countdown program which also shows the tenths of a second; for example from a 10.0 second countdown, it should display 9.9s, 9.8s, ... 0.0s
我必须制作一个倒计时程序,它也显示十分之一秒;例如从 10.0 秒倒计时,它应该显示 9.9s, 9.8s, ... 0.0s
private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) {
timer.start();
timer2.start();
}
Double timeLeft=5000; //5 seconds
Timer timer=new Timer(1,countDown);
Timer timer2=new Timer(1000,countDown2);
ActionListener countDown=new ActionListener()
{
public void actionPerformed(ActionEvent e)
{
timeLeft--;
SimpleDateFormat df=new SimpleDateFormat("mm:ss:S");
jLabel1.setText(df.format(timeLeft));
if(timeLeft<=0)
{
timer.stop();
}
}
};
what happens is it's taking more than 5 seconds to finish the 5 seconds.
发生的事情是完成这 5 秒需要超过 5 秒。
I compared the code above with another Timer
我将上面的代码与另一个计时器进行了比较
int timeLeft2=5;
ActionListener countDown2=new ActionListener()
{
public void actionPerformed(ActionEvent e)
{
timeLeft2--;
jLabel2.setText(String.valueOf(timeLeft2));
if(timeLeft2<=0)
{
time2.stop();
}
}
};
is it natural that they don't get the same?
他们不一样是自然的吗?
回答by MadProgrammer
The time between ticks (the time when actionPerfomed
is called) is variable, it only guarantees that it will be at least n
milliseconds
滴答之间的时间(actionPerfomed
被调用的时间)是可变的,它只保证至少是n
毫秒
Instead of relying on some counter, which could become unreliable over time, you should try and calculate the difference between the time the Timer
was started and the current time, for example...
您应该尝试计算Timer
开始时间和当前时间之间的差异,而不是依赖某些可能会随着时间的推移变得不可靠的计数器,例如......
import java.awt.Dimension;
import java.awt.EventQueue;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.GridBagLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.awt.event.MouseAdapter;
import java.awt.event.MouseEvent;
import java.text.SimpleDateFormat;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;
import javax.swing.Timer;
import javax.swing.UIManager;
import javax.swing.UnsupportedLookAndFeelException;
public class CountDown {
public static void main(String[] args) {
new CountDown();
}
public CountDown() {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
try {
UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
ex.printStackTrace();
}
JFrame frame = new JFrame("Testing");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.add(new TestPane());
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
});
}
public class TestPane extends JPanel {
private Timer timer;
private long startTime = -1;
private long duration = 5000;
private JLabel label;
public TestPane() {
setLayout(new GridBagLayout());
timer = new Timer(10, new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
if (startTime < 0) {
startTime = System.currentTimeMillis();
}
long now = System.currentTimeMillis();
long clockTime = now - startTime;
if (clockTime >= duration) {
clockTime = duration;
timer.stop();
}
SimpleDateFormat df = new SimpleDateFormat("mm:ss:SSS");
label.setText(df.format(duration - clockTime));
}
});
timer.setInitialDelay(0);
addMouseListener(new MouseAdapter() {
@Override
public void mouseClicked(MouseEvent e) {
if (!timer.isRunning()) {
startTime = -1;
timer.start();
}
}
});
label = new JLabel("...");
add(label);
}
@Override
public Dimension getPreferredSize() {
return new Dimension(200, 200);
}
}
}
回答by Adrian Leonhard
Updating the label probably takes more that 1ms, which is why it can't keep up. If you only need to display tenths of a second, simply have your timer update less often.
更新标签可能需要超过 1 毫秒,这就是它无法跟上的原因。如果您只需要显示十分之一秒,只需减少您的计时器更新频率即可。
ActionListener countDown=new ActionListener()
{
public void actionPerformed(ActionEvent e)
{
timeLeft -= 100;
SimpleDateFormat df=new SimpleDateFormat("mm:ss:S");
jLabel1.setText(df.format(timeLeft));
if(timeLeft<=0)
{
timer.stop();
}
}
};
Timer timer=new Timer(100, countdown);