java 带有 JPopupMenu 的 JTable
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JTable with JPopupMenu
提问by mKorbel
how can I prevent triggering and showing JPopupMenu
only if is Mouse Cursor
over selected JTable'Row
如何防止触发和JPopupMenu
仅在Mouse Cursor
过度选择时显示JTable'Row
my question: if is there another way as getBounds
from selected row and determine/compare that with Mouse
position...
我的问题:是否有另一种方式getBounds
从所选行开始并确定/与Mouse
位置进行比较...
my simple sscce demonstrated just un-wanted opposite status, any row could be selected and JPopupMenu
is triggered from whole JTable
我的简单 sscce 展示了不想要的相反状态,可以选择任何行并JPopupMenu
从整个触发JTable
import java.awt.event.*;
import javax.swing.*;
import javax.swing.table.*;
public class TableCheckBox extends JFrame {
private static final long serialVersionUID = 1L;
private JTable table;
public TableCheckBox() {
Object[] columnNames = {"Type", "Company", "Shares", "Price", "Boolean"};
Object[][] data = {
{"Buy", "IBM", new Integer(1000), new Double(80.50), false},
{"Sell", "MicroSoft", new Integer(2000), new Double(6.25), true},
{"Sell", "Apple", new Integer(3000), new Double(7.35), true},
{"Buy", "Nortel", new Integer(4000), new Double(20.00), false}
};
DefaultTableModel model = new DefaultTableModel(data, columnNames);
table = new JTable(model) {
private static final long serialVersionUID = 1L;
@Override
public Class getColumnClass(int column) {
return getValueAt(0, column).getClass();
}
};
table.setPreferredScrollableViewportSize(table.getPreferredSize());
JScrollPane scrollPane = new JScrollPane(table);
add(scrollPane);
createPopupMenu();
}
private void createPopupMenu() {
JPopupMenu popup = new JPopupMenu();
JMenuItem myMenuItem1 = new JMenuItem("cccccccccccccccccccccc");
JMenuItem myMenuItem2 = new JMenuItem("bbbbbbbbbbbbbbbbbbbbbb");
popup.add(myMenuItem1);
popup.add(myMenuItem2);
MouseListener popupListener = new PopupListener(popup);
table.addMouseListener(popupListener);
}
private class PopupListener extends MouseAdapter {
private JPopupMenu popup;
PopupListener(JPopupMenu popupMenu) {
popup = popupMenu;
}
@Override
public void mousePressed(MouseEvent e) {
maybeShowPopup(e);
}
@Override
public void mouseReleased(MouseEvent e) {
if (table.getSelectedRow() != -1) {
maybeShowPopup(e);
}
}
private void maybeShowPopup(MouseEvent e) {
if (e.isPopupTrigger()) {
popup.show(e.getComponent(), e.getX(), e.getY());
}
}
}
public static void main(String[] args) {
SwingUtilities.invokeLater(new Runnable() {
@Override
public void run() {
TableCheckBox frame = new TableCheckBox();
frame.setDefaultCloseOperation(EXIT_ON_CLOSE);
frame.pack();
frame.setLocation(150, 150);
frame.setVisible(true);
}
});
}
}
采纳答案by kleopatra
It's an interesting question, because it highlights missing api on JComponent :-)
这是一个有趣的问题,因为它突出显示了 JComponent 上缺少的 api :-)
As we all know, the recommended way to register popupMenus is to use the componentPopupMenu property. Related api is
众所周知,注册 popupMenus 的推荐方式是使用 componentPopupMenu 属性。相关的api是
void setComponentPopupMenu(JPopupMenu);
JPopupMenu getComponentPopupMenu();
Point getPopupLocation(MouseEvent);
what is missing (and actually needed for this requirement) is
缺少的(并且实际上需要此要求)是
JPopupMenu getComponentPopupMenu(MouseEvent);
this lack is all the more annoying, as the getPopupLocation is called (by AWTEventHelper deep in the LAF) aftergetComponentPopup(). So there's no leeway for a hack like storing the last mouse event which might have triggered the popup and then decide which/if to return popup. And returning null for the location will only result in showing it at the mouse location
这种缺失更加令人讨厌,因为在getComponentPopup()之后调用了 getPopupLocation(由 LAF 深处的 AWTEventHelper )。因此,对于像存储可能触发弹出窗口的最后一个鼠标事件,然后决定哪个/是否返回弹出窗口这样的 hack 没有余地。并且为该位置返回 null 只会导致在鼠标位置显示它
The only (dirty) hack (around my utter reluctance to get my hands dirty with a MouseListener ;-) is to override getComponentPopup and decide there whether or not to return it based on current mouse position
唯一的(肮脏的)hack(围绕我完全不愿意用 MouseListener 弄脏我的手;-)是覆盖 getComponentPopup 并根据当前鼠标位置决定是否返回它
table = new JTable(model) {
/**
* @inherited <p>
*/
@Override
public JPopupMenu getComponentPopupMenu() {
Point p = getMousePosition();
// mouse over table and valid row
if (p != null && rowAtPoint(p) >= 0) {
// condition for showing popup triggered by mouse
if (isRowSelected(rowAtPoint(p))) {
return super.getComponentPopupMenu();
} else {
return null;
}
}
return super.getComponentPopupMenu();
}
};
the side-effect is that popup showing isn't triggered by keyboard as long as the mouse is anywhere above the table, which might or not be a problem.
副作用是只要鼠标在桌子上方的任何位置,弹出显示就不会由键盘触发,这可能是也可能不是问题。
回答by Hovercraft Full Of Eels
Are you looking for something like this perhaps?
你在寻找这样的东西吗?
To show popup over selected row(s) only
仅在选定行上显示弹出窗口
private void maybeShowPopup(MouseEvent e) {
if (e.isPopupTrigger()) {
// get row that pointer is over
int row = table.rowAtPoint(e.getPoint());
// if pointer is over a selected row, show popup
if (table.isRowSelected(row)) {
popup.show(e.getComponent(), e.getX(), e.getY());
}
}
}
Or the converse, to prevent popup from showing over selected rows only:
或者反过来,为了防止弹出窗口只显示在选定的行上:
private void maybeShowPopup(MouseEvent e) {
if (e.isPopupTrigger()) {
int row = table.rowAtPoint(e.getPoint());
int[] selectedRows = table.getSelectedRows();
if (!table.isRowSelected(row)) {
popup.show(e.getComponent(), e.getX(), e.getY());
}
}