php Yii app()->createUrl 用于视图操作
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Yii app()->createUrl for view action
提问by JalalJaberi
I use generated actions by Gii in a module said News. I have normal view action that works with an id parameter (such as example.com/news/view/id/1).
When I use this line of code:
我在名为 News 的模块中使用 Gii 生成的操作。我有使用 id 参数（例如example.com/news/view/id/1）的普通视图操作。
当我使用这行代码时：
Yii::app()->createUrl("news/view",array("id"=>$data->primaryKey))
It generates example.com/news/1(if $data->primaryKeyis 1). It is not correct.
When I use this line of code:
它生成example.com/news/1（如果$data->primaryKey是 1）。这是不正确的。
当我使用这行代码时：
Yii::app()->createUrl("news/view/id/",array("id"=>$data->primaryKey))
It generates example.com/news/id/id/1(if $data->primaryKeyis 1).
它生成example.com/news/id/id/1（如果$data->primaryKey是 1）。
I am so confused! in first situation, this function doesn't generate id as a parameter name, and in second situation, it does! but after manually added id.
What shoud I do to make correct url format with this function?
我感到很困惑！在第一种情况下，此函数不会生成 id 作为参数名称，而在第二种情况下，它会生成！但是在手动添加id之后。
我应该怎么做才能使用此功能制作正确的 url 格式？
Edit:news is a module. I changed the line of code as:
编辑：新闻是一个模块。我将代码行更改为：
Yii::app()->createUrl("news/default/view/id/",array("id"=>$data->primaryKey))
It generates example.com/news/default/view/id/1that is correct, but I don't want that default!
它生成的example.com/news/default/view/id/1是正确的，但我不想要那个默认值！
回答by TotPeRo
In config file you have something like this:
在配置文件中你有这样的东西：
'urlManager'=>array(
'urlFormat'=>'path',
'rules'=>array(
'<controller:\w+>/<id:\d+>'=>'<controller>/view',
'<controller:\w+>/<action:\w+>/<id:\d+>'=>'<controller>/<action>',
'<controller:\w+>/<action:\w+>'=>'<controller>/<action>',
),
),
this create how to look the URL.
这将创建如何查看 URL。
You not need to write the idparameter when you create URL because is default. Look on the urlmanager rules:
id创建 URL 时不需要写入参数，因为它是默认值。查看 urlmanager 规则：
Yii::app()->createUrl("news/view/",array("id"=>$data->primaryKey)) => example.com/news/id/1
On module defaut:
在模块默认上：
Yii::app()->createUrl('/news/default/view', array('id' => $data->primaryKey))
You need to create the urlmanager rule... how you want to look at your URL. More details here.
您需要创建 urlmanager 规则...您希望如何查看您的 URL。更多细节在这里。
回答by George Sovetov
Use
用
'rules'=>array(
'news/<controller:\w+>/<id:\d+>'=>'news/<controller>/view',
'news/<controller:\w+>/<action:\w+>/<id:\d+>'=>'news/<controller>/<action>',
'news/<controller:\w+>/<action:\w+>'=>'news/<controller>/<action>',
),
if you have a module names news.
如果你有一个模块名称news。
You can try to replace newswith regex but you will face problems with urls matched by several regexes if your regex is too broad. Use something like <module:news|accounting|people>in rules array key and <module>in rules array value.
您可以尝试news用 regex替换，但如果您的 regex 太宽泛，您将面临多个 regex 匹配的 url 的问题。<module:news|accounting|people>在规则数组键和<module>规则数组值中使用类似的东西。
If you need more sophisticated url management, or if you cannot solve your task with regexes, you can always extend CUrlManager.
如果您需要更复杂的 url 管理，或者如果您无法使用正则表达式解决您的任务，您可以随时扩展 CUrlManager。
回答by f_anto
trying to check it on this directory: protected/config/main.php sir.
试图在这个目录上检查它：protected/config/main.php 先生。
urlManager'=>array(
'urlFormat'=>'path',
'rules'=>array(
'<controller:\w+>/<id:\d+>'=>'<controller>/view',
'<controller:\w+>/<action:\w+>/<id:\d+>'=>'<controller>/<action>',
'<controller:\w+>/<action:\w+>'=>'<controll<>er>/<action>',
),
),
Please notice is that routed well? :)
请注意，路由是否良好？:)
