javascript 数组上的 ParseInt() 方法
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/12192450/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
ParseInt() method on array
提问by Carlos
I am wondering to how to get number from an array. I have tried its give me NaN error
我想知道如何从数组中获取数字。我试过它给我 NaN 错误
<script type="text/javascript">
$(function(){
var Arr = [ 'h78em', 'w145px', 'w13px' ]
alert(parseInt(Arr[0]))
})
</script>
回答by Fabrizio Calderan
try with
尝试
+Arr[0].replace(/\D/g, '');
Example fiddle: http://jsfiddle.net/t6yCV/
小提琴示例：http: //jsfiddle.net/t6yCV/
Starting +is working like parseInt()and it is necessary if you need to perform some mathematical operation with the number obtained: in fact
开始+工作就像这样parseInt()，如果您需要对获得的数字执行一些数学运算，这是必要的：事实上
typeof Arr[0].replace(/\D/g,'') // String
typeof +Arr[0].replace(/\D/g,'') // Number
回答by KooiInc
Try:
尝试：
['h78em', 'w145px', 'w13px']
.map(function(a){return ~~(a.replace(/\D/g,''));});
//=> [78, 145, 13]
Or use a somewhat more elaborate Stringprototype extension:
或者使用更复杂的String原型扩展：
String.prototype.intsFromString = function(combine){
var nums = this.match(/\d{1,}/g);
return !nums ? 0
: nums.length>1 ? combine ? ~~nums.join('')
: nums.map(function(a){return ~~a;})
: ~~nums[0];
};
// usage
'abc23'.intsFromString(); //=> 23
'3abc121cde'.intsFromString(); //=> [3,121]
'3abc121cde'.intsFromString(true); //=> 3121
'abcde'.intsFromString(); //=> 0
// and ofcourse
['h78em', 'w145px', 'w13px'].map(function(a){return a.intsFromString();});
//=> [78, 145, 13]
回答by Dhanasekar
Try this:
试试这个：
var Arr = [ 'h78em', 'w145px', 'w13px' ]
function stringToNum(str){
return str.match(/\d+/g);
}
alert(stringToNum(Arr[0]));
回答by gabitzish
You can build a function that builds the number from your string:
您可以构建一个从字符串中构建数字的函数：
function stringToNum(str){
num = 0;
for (i = 0; i < str.length; i++)
if (str[i] >= '0' && str[i] <= '9')
num = num * 10 + parseInt(str[i]);
return num;
}
jsFiddle : http://jsfiddle.net/8WwHh/
jsFiddle：http: //jsfiddle.net/8WwHh/
回答by MAK
Yet another quick and dirty solution:
另一个快速而肮脏的解决方案：
alert(Arr[0].match("\d+"));
回答by yao lu
Try it,this regex is better
试试看，这个正则表达式更好
parseInt('h343px'.replace(/^[a-zA-Z]+/,''),10)
