Linux 在 Bash 中使用下划线“_”无法正确打印文件名
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Filename not printing correctly with underscore "_" in Bash
提问by Mahakaal
I am using this
我正在使用这个
DATE_FOLDER=$(date +"%b-%d-%a-%G")
FILENAME="HOME_$date1.tar.gz"
echo $BACKUP_DESTINATION/$DATE_FOLDER/$FOLDERNAME_$FILENAME
My output is
我的输出是
home/May-04-Wed-2011/HOME_May-04-0718PM-2011.tar.gz
but if I use -instead of underscore _
但如果我使用 -而不是下划线_
echo $BACKUP_DESTINATION/$DATE_FOLDER/$FOLDERNAME-$FILENAME
then my ouput is correct
那么我的输出是正确的
/home/May-04-Wed-2011/vmware-HOME_May-04-0717PM-2011.tar.gz
Why is that?
这是为什么？
采纳答案by Ignacio Vazquez-Abrams
_is a valid character for a variable name, and $FOLDERNAME_doesn't exist.
_是变量名的有效字符，$FOLDERNAME_不存在。
echo "$BACKUP_DESTINATION/$DATE_FOLDER/${FOLDERNAME}_$FILENAME"
回答by user4471187
The problem is here : HOME_$date1.tar.gzand also here: _$FILENAME.
If you use _$then the $is escaped.
问题在这里 :HOME_$date1.tar.gz也在这里: _$FILENAME。如果您使用_$，$则转义。
Nevertheless you can do it with: \\_$.
Then you escape the _with the \and the $will be interpreted as you are used to it.
不过，您可以使用：\\_$. 然后你_用 the转义 the\并且 the $will 被解释为你习惯了。
