Python 类型错误：“列表”对象不可调用
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TypeError: 'list' object is not callable
提问by Rodrigo Villalta
I can't find the problem i'm facing...
this is exactly what the error tells me:
我找不到我面临的问题......
这正是错误告诉我的：
File "C:/Users/Rodrigo Villalta/Desktop/listasparimpar.py", line 38,
in listas_par_impar
if lista2(m) > lista2 [m+1]: TypeError: 'list' object is not callable
This is the code:
这是代码：
def listas_par_impar(lista,lista2):
lista3=[]
lista4=[]
for i in lista2:
if i % 2 == 0:
lista=lista+[i]
else:
pass
for i in lista:
if i %2 != 0:
lista2=lista2+[i]
else:
pass
for i in lista:
if i%2==0:
if i not in lista3:
lista3=lista3+[i]
lista=lista[1:]
for i in lista2:
if i%2!=0:
if i not in lista4:
lista4=lista4+[i]
lista=lista[1:]
for recorrido in range(1,len(lista)):
for posicion in range(len(lista)-recorrido):
if lista(posicion) > lista [posicion+1]:
lista[posicion], lista[posicion+1] = lista[posicion+1], lista[posicion]
for r in range(1,len(lista2)):
for m in range(len(lista2)-r):
if lista2(m) > lista2 [m+1]:
lista2[m], lista2[m+1] = lista2[m+1], lista2[m]
print (lista4, lista3)
采纳答案by abarnert
In this line:
在这一行：
if lista2(m) > lista2 [m+1]:
… you've written lista2(m)instead of lista2[m].
... 你写的lista2(m)不是lista2[m].
This means you're trying to call lista2like a function, with argument m. What you wanted to do is index lista2like a list, with index m.
这意味着您正在尝试lista2像函数一样使用参数进行调用m。您想要做的是lista2像列表一样索引，带有 index m。
回答by NeverForgetY2K
if lista2(m) > lista2 [m+1]:
Should be:
应该：
if lista2[m] > lista2 [m+1]:
