Javascript 为什么 JSON.parse 不起作用？
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Why JSON.parse is not working?
提问by Frias
I set the dataType to 'text' because I don't want to Jquery parse my JSON automatically. My code is the following:
我将 dataType 设置为“text”，因为我不想让 Jquery 自动解析我的 JSON。我的代码如下：
var membId = '5';
$('#submitNewDescription').live('click',function(){
//An ajax request is made to update the DB
$.ajax({
url: '../../cgi-bin/qualification.py',
type: 'POST',
data: ({newDescription:$('#newDescription').val(),id:membId}),
dataType: 'text',
cache: 'false',
success: function(data){
json = JSON.parse(data);
console.log(data);
console.log(json);
}
});
});
And it returns that string: {"error":["ORA-01031 insufficient privileges"]} in both console.log commands. It means that the parse isn't working since it doesn't return a JavaScript object. JSONLint says to me that is a valid JSON.
它在两个 console.log 命令中都返回该字符串：{"error":["ORA-01031 enough privileges"]}。这意味着解析不起作用，因为它不返回 JavaScript 对象。JSONLint 告诉我这是一个有效的 JSON。
Anyone has an idea of what is happening?
任何人都知道发生了什么？
Thanks
谢谢
EDIT
编辑
I can set to 'json', it is not problem. The problem is that JSON.parse and $.parseJSON should work. Since they are not, I changed 'dataType' to 'json', but the same string is returned. I have no idea what is happening.
我可以设置为'json'，没问题。问题是 JSON.parse 和 $.parseJSON 应该可以工作。由于它们不是，我将“dataType”更改为“json”，但返回了相同的字符串。我不知道发生了什么。
回答by Brad Christie
Probably because you're looking for $.parseJSONinstead? Also I beievejQuery will look at the data and make a best-guess at parsing it before passing it off to the callback. So, if it looks like JSON chances are jQuery's already giving you a JavaScript object back which then can'tbe re-parsed using JSON.parse/$.parseJSON.
可能是因为你正在寻找$.parseJSON？此外，我相信jQuery 会查看数据并在将其传递给回调之前对其进行最佳猜测。因此，如果看起来 JSON 很有可能是 jQuery 已经为您提供了一个 JavaScript 对象，然后无法使用JSON.parse/重新解析该对象$.parseJSON。
You can also change your dataTypefield to 'json' and let jQuery do it for you...
您还可以将您的dataType字段更改为 'json' 并让 jQuery 为您完成...
回答by Santosh Linkha
change dataType: 'text'to dataType: "json"and also JSON.parseto $.parseJSON
更改dataType: 'text'为dataType: "json"并且也更改JSON.parse为$.parseJSON
回答by Edgar
The JSONlibrary doesn't exist in all browsers. You might need to include your own like http://developer.yahoo.com/yui/json/
该JSON库并非在所有浏览器中都存在。您可能需要像http://developer.yahoo.com/yui/json/一样包含自己的
Or like the others suggested, use the jQuery one. You might also want to declare jsonlike var json = ...
或者像其他人建议的那样，使用 jQuery 一个。您可能还想声明json像var json = ...
回答by Gene Bo
In my case, I got it to work as follows:
就我而言，我让它按如下方式工作：
- from the server (a servlet), I specified json as the data type of the response
- the jquery call then already parses the response param into a JSON object (so I didn't need to run $.parseJSON) ... thank you https://stackoverflow.com/a/6465506/2162226!
- 从服务器（一个 servlet），我指定 json 作为响应的数据类型
- jquery 调用然后已经将响应参数解析为 JSON 对象（所以我不需要运行 $.parseJSON）...谢谢https://stackoverflow.com/a/6465506/2162226！
Notice I can: access the json field directly in the response object
注意我可以：直接在响应对象中访问 json 字段
$.ajax({
type: "POST",
url: baseUrl,
dataType: "json",
data: theData,
success: function(response) {
alert(' status = ' + response.status);
processResponseJSON(response);
},
