C++ 如何使用 iomanip 的 setw、setfill 和 left/right？Setfill 不会停止输出
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How do I use iomanip's setw, setfill, and left/right? Setfill isn't stopping its output
提问by user3448821
I'm trying to get my output to look like this:
我试图让我的输出看起来像这样：
size time1 time2
-------------------------------
10 4 8
100 48 16
1000 2937 922
10000 123011 3902
100000 22407380 830722
And I know I need to use setw(), setfill(), and left. However, my attempts keep giving me incorrect output. Here is one example of my code:
我知道我需要使用setw()，setfill()和left。但是，我的尝试不断给我错误的输出。这是我的代码的一个示例：
std::cout << "size" << std::setw(20) << "time" << std::setw(20) << "time2\n";
std::cout << std::setfill('-') << std::setw(60) << "-" << std::endl;
run = 10;
for(int i = 0; i < 5; i++) {
std::cout << run;
run *= 10;
std::cout << std::setw(20) << std::left << time1[i];
std::cout << std::setw(20) << std::left << time2[i] << "\n";
}
And here's the output:
这是输出：
size time1 time2
------------------------------------------------------------
103-------------------13------------------
100171-----------------199-----------------
100013183---------------667-----------------
10000670130--------------8205----------------
10000014030798-------------1403079888---------
I've tried changing the order that I'm using setw(), setfill(), and left, but I'm just flying blind right now. I've also searched iomanip tutorials. I'm following the directions--as far as I can tell--but I'm still not getting it.
我试过，我使用改变顺序setw()，setfill()和left，但我只是盲目飞行现在。我还搜索了 iomanip 教程。我正在遵循指示——据我所知——但我仍然没有明白。
How do I stop the setfill()from running over? How do I justify left but use setw()to stop the numbers from running into each other?
我如何阻止setfill()跑过？我如何证明左对齐但用于setw()阻止数字相互碰撞？
采纳答案by sj0h
How about:
怎么样：
std::cout << "size" << std::setw(20) << "time" << std::setw(20) << "time2\n";
std::cout << std::setfill('-') << std::setw(60) << "-" << std::endl;
run = 10;
std::cout << std::setfill(' '); //fill with spaces
for(int i = 0; i < 5; i++) {
std::cout << std::setw(20) << std::left << run; // fill the run column
run *= 10;
std::cout << std::setw(20) << std::left << time1[i];
std::cout << std::setw(20) << std::left << time2[i] << "\n";
}
回答by oneofthesixbillion
sj0h's answer is great except the titles don't quite line up. To fix it I started the title line with "left" and "setw", I also had to end with "endl" instead of "\n".
sj0h 的回答很好，只是标题不太一致。为了修复它，我以“left”和“setw”开始标题行，我还必须以“endl”而不是“\n”结尾。
std::cout << std::left << std::setw(20) << "size" << std::setw(20) << "time" << std::setw(20) << "time2" << std::endl;
std::cout << std::setfill('-') << std::setw(60) << "-" << std::endl;
run = 10;
std::cout << std::setfill(' '); //fill with spaces
for(int i = 0; i < 10; i++) {
std::cout << std::setw(20) << std::left << run; // fill the run column
run *= 10;
std::cout << std::setw(20) << std::left << time1[i];
std::cout << std::setw(20) << std::left << time2[i] << std::endl;
}
