C++ 如何以十六进制格式将数据附加到 std::string？
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How can I append data to a std::string in hex format?
提问by samoz
I have an existing std::stringand an int. I'd like to concatenate the ASCII (string literal) hexadecimal representation of the integer to the std::string.
我有一个现有的std::string和一个int. 我想将整数的 ASCII（字符串文字）十六进制表示连接到std::string.
For example:
例如：
std::string msg = "Your Id Number is: ";
unsigned int num = 0xdeadc0de; //3735929054
Desired string:
所需的字符串：
std::string output = "Your Id Number is: 0xdeadc0de";
Normally, I'd just use printf, but I can't do this with a std::string (can I?)
通常，我只会使用 printf，但我不能用 std::string 来做到这一点（我可以吗？）
Any suggestions as to how to do this?
关于如何做到这一点的任何建议？
回答by xtofl
Use a stringstream. You can use it as any other output stream, so you can equally insert std::hexinto it. Then extract it's stringstream::str()function.
使用字符串流。您可以将其用作任何其他输出流，因此您可以同样插入std::hex其中。然后提取它的stringstream::str()功能。
std::stringstream ss;
ss << "your id is " << std::hex << 0x0daffa0;
const std::string s = ss.str();
回答by Meredith L. Patterson
Building on xtofl's answer, the header you're looking for is <iomanip>. This is where std::hex, std::dec, and std::octlive, all of which can be directed into streams such that whatever gets sent into the stream after them is converted to that base.
基于 xtofl 的答案，您要查找的标题是<iomanip>. 这是 where std::hex, std::dec, 和std::octlive ，所有这些都可以被定向到流中，这样在它们被转换到那个基础之后发送到流中的任何东西。
回答by DevByStarlight
I believe 'string' only forward declares std::stringstream. So you also need to include:
我相信 'string' 只向前声明 std::stringstream。所以你还需要包括：
#include <sstream>
