C语言 将文件读取为字节数组
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Read a file as byte array
提问by alissonlacerda
I have an assignment for coding a Huffman algorithm. I have the whole problem organized in my head, but I'm having some trouble with file handling.
我有一个编写霍夫曼算法的作业。我脑子里想通了整个问题，但是我在处理文件时遇到了一些麻烦。
The problem is: the algorithm is supposed to compress ANYkind of file.
问题是：该算法应该压缩任何类型的文件。
My solution: read the file as a byte array, then with an int array[256]={0}for each byte, get it's int ncorresponding value and increment the array[n]. If I didn't make it clear, let me know.
我的解决方案：将文件作为字节数组读取，然后int array[256]={0}对每个字节使用一个，获取它的int n相应值并增加array[n]. 如果我没有说清楚，请告诉我。
So, I've done lots of researching, but don't understand how to get bytes from ANY kind of file and how to handle them.
所以，我做了很多研究，但不明白如何从任何类型的文件中获取字节以及如何处理它们。
回答by user1274193
FILE *fileptr;
char *buffer;
long filelen;
fileptr = fopen("myfile.txt", "rb"); // Open the file in binary mode
fseek(fileptr, 0, SEEK_END); // Jump to the end of the file
filelen = ftell(fileptr); // Get the current byte offset in the file
rewind(fileptr); // Jump back to the beginning of the file
buffer = (char *)malloc(filelen * sizeof(char)); // Enough memory for the file
fread(buffer, filelen, 1, fileptr); // Read in the entire file
fclose(fileptr); // Close the file
Now you have an array of bytes containing the file's contents.
现在您有一个包含文件内容的字节数组。
回答by Suryavanshi
How about trying binary file IO:
试试二进制文件 IO 怎么样：
FILE *f=fopen("example.bin","rb");
char c;
//loop for each byte to the end
{
size_t fread(&c, (size_t)1, (size_t) 1, f);
array[c]++;
}
Or something along the lines!!
或者类似的东西！！
