Spring MVC @RestController 和重定向
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/29085295/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Spring MVC @RestController and redirect
提问by alexanoid
I have a REST endpoint implemented with Spring MVC @RestController. Sometime, depends on input parameters in my controller I need to send http redirect on client.
我有一个用 Spring MVC @RestController 实现的 REST 端点。有时，取决于我的控制器中的输入参数，我需要在客户端上发送 http 重定向。
Is it possible with Spring MVC @RestController and if so, could you please show an example ?
Spring MVC @RestController 是否可以使用，如果可以，请举例说明？
回答by Neil McGuigan
Add an HttpServletResponseparameter to your Handler Method then call response.sendRedirect("some-url");
HttpServletResponse向您的处理程序方法添加一个参数，然后调用response.sendRedirect("some-url");
Something like:
就像是：
@RestController
public class FooController {
@RequestMapping("/foo")
void handleFoo(HttpServletResponse response) throws IOException {
response.sendRedirect("some-url");
}
}
回答by Arne Burmeister
To avoid any direct dependency on HttpServletRequestor HttpServletResponseI suggest a "pure Spring" implementation returning a ResponseEntitylike this:
为了避免任何直接依赖HttpServletRequest或HttpServletResponse我建议使用“纯 Spring”实现返回这样的ResponseEntity：
HttpHeaders headers = new HttpHeaders();
headers.setLocation(URI.create(newUrl));
return new ResponseEntity<>(headers, HttpStatus.MOVED_PERMANENTLY);
If your method always returns a redirect, use ResponseEntity<Void>, otherwise whatever is returned normally as generic type.
如果您的方法总是返回重定向，请使用ResponseEntity<Void>，否则通常以泛型类型返回。
回答by DhatGuy
Came across this question and was surprised that no-one mentioned RedirectView. I have just tested it, and you can solve this in a clean 100% spring way with:
遇到这个问题，很惊讶没有人提到 RedirectView。我刚刚测试了它，你可以用干净的 100% 弹簧方式解决这个问题：
@RestController
public class FooController {
@RequestMapping("/foo")
public RedirectView handleFoo() {
return new RedirectView("some-url");
}
}
回答by Eric Wang
redirectmeans http code 302, which means Foundin springMVC.
redirect表示 http 代码302，也就是Found在 springMVC 中。
Here is an util method, which could be placed in some kind of BaseController:
这是一个 util 方法，它可以放在某种类型中BaseController：
protected ResponseEntity found(HttpServletResponse response, String url) throws IOException { // 302, found, redirect,
response.sendRedirect(url);
return null;
}
But sometimes might want to return http code 301instead, which means moved permanently.
但有时可能想要返回 http 代码301，这意味着moved permanently.
In that case, here is the util method:
在这种情况下，这是 util 方法：
protected ResponseEntity movedPermanently(HttpServletResponse response, String url) { // 301, moved permanently,
return ResponseEntity.status(HttpStatus.MOVED_PERMANENTLY).header(HttpHeaders.LOCATION, url).build();
}
回答by árpád Magosányi
As the redirections are usually needed in a not-straightforward path, I think throwing an exception and handling it later is my favourite solution.
由于重定向通常需要在不直接的路径中进行，我认为抛出异常并稍后处理是我最喜欢的解决方案。
Using a ControllerAdvice
使用 ControllerAdvice
@ControllerAdvice
public class RestResponseEntityExceptionHandler
extends ResponseEntityExceptionHandler {
@ExceptionHandler(value = {
NotLoggedInException.class
})
protected ResponseEntity<Object> handleNotLoggedIn(
final NotLoggedInException ex, final WebRequest request
) {
final String bodyOfResponse = ex.getMessage();
final HttpHeaders headers = new HttpHeaders();
headers.add("Location", ex.getRedirectUri());
return handleExceptionInternal(
ex, bodyOfResponse,
headers, HttpStatus.FOUND, request
);
}
}
The exception class in my case:
在我的例子中的异常类：
@Getter
public class NotLoggedInException extends RuntimeException {
private static final long serialVersionUID = -4900004519786666447L;
String redirectUri;
public NotLoggedInException(final String message, final String uri) {
super(message);
redirectUri = uri;
}
}
And I trigger it like this:
我像这样触发它：
if (null == remoteUser)
throw new NotLoggedInException("please log in", LOGIN_URL);
回答by skuarch
if you @RestController returns an Stringyou can use something like this
如果你@RestController 返回一个字符串，你可以使用这样的东西
return "redirect:/other/controller/";
and this kind of redirect is only for GETrequest, if you want to use other type of request use HttpServletResponse
而这种重定向只针对GET请求，如果你想使用其他类型的请求，请使用 HttpServletResponse
