bash 我们如何根据unix中的给定日期获得工作日
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/46024251/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How can we get weekday based on given date in unix
提问by Divya S
From a given date in %m-%d-%Y format we should determine what day it is Please help me with the command
从 %m-%d-%Y 格式的给定日期，我们应该确定它是哪一天请帮我使用命令
like if i pass a date like 09-01-2017 output should be Friday
就像我传递一个日期，比如 09-01-2017 输出应该是星期五
回答by Rajeev Ranjan
DayOfWeek=$(date +%A)
This would yield the day of week monday-sundayIf your input date is strictly in the format MM-DD-YYYY, use the following
这将产生星期几monday-sunday如果您的输入日期严格按照格式MM-DD-YYYY，请使用以下内容
IFS='-' read -ra ADDR <<< "09-01-2017"
formattedDate=${ADDR[2]}-${ADDR[0]}-${ADDR[1]}
date -d $formattedDate +%A
The first line tokenizes the components of the date and the second rearranges them
第一行标记日期的组成部分，第二行重新排列它们
回答by Juan Manuel García
If you have your date like this:
如果你的约会对象是这样的：
d="09-01-2017"
you need to reformat it to "YYYY-MM-DD"
您需要将其重新格式化为“YYYY-MM-DD”
date -d $(echo $d|awk -F- '{print "-" "-" }') +%A # DOW
回答by nagendra547
Very simple. Just use the date command itself with correct options.
很简单。只需使用带有正确选项的 date 命令本身即可。
$ date -j -f '%m-%d-%Y' "09-01-2017" +'%A'
Friday
回答by stack0114106
You can pass it as %m/%d%Y which gets recognized by the date command.
您可以将它作为 %m/%d%Y 传递，它会被 date 命令识别。
$ date --date="`echo 09-01-2017| sed -e 's/-/\//g' `" +'%A'
Friday
To verify it, pass %F to get it in ISO format
要验证它，请传递 %F 以获取 ISO 格式
$ date --date="`echo 09-01-2017| sed -e 's/-/\//g' `" +'%A %F'
Friday 2017-09-01
