C# 正确实现 GetHashCode
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Implementing GetHashCode correctly
提问by Zivka
I'd like to hear from the community on how I should go about implementing GetHashCode (or override it) for my object. I understand I need to do so if I override the equals method. I have implemented it a fair amount of times, sometimes just calling the base method. I understand that my object should equal another instance of the object if it contains the same details (members). What is the best way to get a hash code from the class's members?
我想听听社区关于我应该如何为我的对象实现 GetHashCode（或覆盖它）的消息。我知道如果我覆盖了 equals 方法，我需要这样做。我已经实现了很多次，有时只是调用基本方法。我明白如果我的对象包含相同的细节（成员），它应该等于对象的另一个实例。从班级成员那里获取哈希码的最佳方法是什么？
采纳答案by jason
Let's say your class looks like this:
假设您的课程如下所示：
class Frob {
public string Foo { get; set; }
public int Bar { get; set; }
public double FooBar { get; set; }
}
Let's say you define equals so that two instances of Frobare equal if their Fooand their Barare equal, but FooBardoesn't matter.
假设您定义了 equals，因此Frob如果它们Foo和它们Bar相等，则它们的两个实例是相等的，但这FooBar并不重要。
Then you should define GetHashCodein terms of Fooand Bar. One way is like this:
那么你应该GetHashCode用Foo和来定义Bar。一种方法是这样的：
return this.Foo.GetHashCode() * 17 + this.Bar.GetHashCode();
Basically, you just want to incorporate all the fields that go into defining the equality. One way is to just keep accumulating and multiplying by 17 like I've done. It's fast, it's simple, it's correct, and it usually gives a good distribution.
基本上，您只想合并用于定义相等性的所有字段。一种方法是像我所做的那样继续累积并乘以 17。它快速、简单、正确，而且通常提供良好的分布。
