MySQL Laravel 加入 3 个表

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时间:2020-08-31 18:37:08  来源:igfitidea点击:

Laravel join with 3 Tables

mysqlsqldatabasejoinlaravel

提问by Plic Pl

I am building a Twitter-like app. There is a Feed in which I want to only show posts of Users who I follow.

我正在构建一个类似 Twitter 的应用程序。有一个供稿,我只想显示我关注的用户的帖子。

I tried everything with joins, but nothing seems to work.

我尝试了所有连接,但似乎没有任何效果。

I have 3 tables: Users, Followers, Shares

我有 3 个表:Users, Followers,Shares

The Tables look like this:

表格如下所示:

Users: id

用户id

Followers: user_id, follower_id

追随者user_idfollower_id

Shares: user_id

股份user_id

What I need to get is "ALL Shares WHERE share.user_id = followers.follower_id" "ANDWHERE followers.user_id = users.id"

我需要得到的是“所有共享 WHERE share.user_id = follower.follower_id”“ANDWHERE follower.user_id = users.id”

Assume, the users.id is 3, I tried this:

假设 users.id 是 3,我试过这个:

$shares = DB::table('shares')
        ->leftjoin('followers', 'shares.user_id', '=', 'followers.follower_id')
        ->leftjoin('users', 'followers.user_id', '=', 'users.id')
        ->where('users.id', 3)
        ->where('shares.user_id', 'followers.follower_id')
        ->get();

But it doesnt work.

但它不起作用。

Any help is appreciated :)

任何帮助表示赞赏:)

回答by vFragosop

I believe your join is wrong:

我相信你的加入是错误的:

$shares = DB::table('shares')
    ->join('users', 'users.id', '=', 'shares.user_id')
    ->join('followers', 'followers.user_id', '=', 'users.id')
    ->where('followers.follower_id', '=', 3)
    ->get();

I also suggest you to name your table as followsinstead, it feels a bit more natural to say user has many followers through followsand user has many followees through follows.

我还建议您将您的表命名为follows,这样说user has many followers through follows和感觉更自然一些user has many followees through follows

Example

例子

$shares = DB::table('shares')
    ->join('users', 'users.id', '=', 'shares.user_id')
    ->join('follows', 'follows.user_id', '=', 'users.id')
    ->where('follows.follower_id', '=', 3)
    ->get();

Model approach

模型方法

I didn't realize you were using DB::queries and not models. So I'm fixing the answer and providing a lot more clarity. I suggest you use models, it's a lot easier for those beginning with the framework and specially SQL.

我没有意识到您使用的是DB::查询而不是模型。所以我正在修复答案并提供更多清晰度。我建议你使用模型,对于那些从框架开始,特别是 SQL 的人来说,这要容易得多。

Example of models:

模型示例:

class User extends Model {
    public function shares() {
        return $this->hasMany('Share');
    }
    public function followers() {
        return $this->belongsToMany('User', 'follows', 'user_id', 'follower_id');
    }
    public function followees() {
        return $this->belongsToMany('User', 'follows', 'follower_id', 'user_id');
    }
}
class Share extends Model {
    public function user() {
        return $this->belongsTo('User');
    }
}

Example of Model usage:

模型使用示例:

$my = User::find('my_id');

// Retrieves all shares by users that I follow
// eager loading the "owner" of the share
$shares = Share::with('user')
    ->join('follows', 'follows.user_id', '=', 'shares.user_id')
    ->where('follows.follower_id', '=', $my->id)
    ->get('shares.*'); // Notice the shares.* here

// prints the username of the person who shared something
foreach ($shares as $share) {
    echo $share->user->username;
}

// Retrieves all users I'm following
$my->followees;

// Retrieves all users that follows me
$my->followers;

回答by JM4

In terms of general MySQL syntax, this is best written:

就一般 MySQL 语法而言,最好这样写:

SELECT * FROM USER a JOIN FOLLOWERS b ON (a.id = b.user_id) JOIN SHARES c on (b.follower_id = c.user_id) WHERE a.id = 3

will return a data set of all followers and their respective shares.

将返回所有关注者及其各自份额的数据集。

I believe you would want the following in Laravel

我相信你会在 Laravel 中想要以下内容

DB::table('USER')
  ->join('FOLLOWERS', 'USER.id', '=', 'FOLLOWERS.user_id')
  ->join('SHARES', 'FOLLOWERS.follower_id', '=', 'SHARES.user_id')
  ->where('USER.id', 3)
  ->get();

回答by svin

Instead of

代替

    ->where('shares.user_id', 'followers.follower_id')

It should be

它应该是

    ->whereRaw('shares.user_id=followers.follower_id')

because on the original example the 'followers.follower_id' is interpreted as a string.

因为在原始示例中,'followers.follower_id' 被解释为字符串。

回答by Mad an

$shares = DB::table('users')
->leftjoin('followers', 'users.user_id', '=', 'followers.follower_id')
->leftjoin('shares', 'shares.user_id', '=', 'users.id')
->where('users.id', 3)
->get();

Take a look

看一看

回答by Ak-Wahid

$data[shares] = DB::table('shares')
        ->leftjoin('followers', 'shares.user_id', '=', 'followers.follower_id')
        ->leftjoin('users', 'users.id', '=', 'users.id')
        ->where('users.id','=', 3)
        ->get();

to see results.

查看结果。

print_r($data[shares]);die;

for other query Simply give discription of your table

对于其他查询只需给出您的表的描述