java 未捕获的 Ext.Error:您正在尝试解码无效的 JSON 字符串:使用 Ext JS 和 Spring MVC 提交表单

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时间:2020-10-31 05:53:17  来源:igfitidea点击:

Uncaught Ext.Error: You're trying to decode an invalid JSON String: Form Submission using Ext JS and Spring MVC

javaspring-mvcextjs4form-submitjson

提问by tech_enthusiast

I am getting the following error after submitting my Ext JS form:

提交 Ext JS 表单后出现以下错误:

Uncaught Ext.Error: You're trying to decode an invalid JSON String

未捕获的 Ext.Error:您正在尝试解码无效的 JSON 字符串

JS:

JS:

Ext.onReady(function() {

        var simple = Ext.create('Ext.form.Panel', {

                    frame : true,
                    title : 'Login Form',
                    bodyStyle : 'padding:5px 5px 0',
                    width : 350,
                    fieldDefaults : {
                        msgTarget : 'side',
                        labelWidth : 75
                    },
                    defaultType : 'textfield',
                    defaults : {
                        anchor : '100%'
                    },

                    items : [{
                                fieldLabel : 'User Name',
                                name : 'userName',
                                allowBlank : false,
                                emptyText : 'UserName'
                            }, {
                                fieldLabel : 'Password',
                                name : 'password',
                                allowBlank : false,
                                inputType : 'password',
                                emptyText : 'Password'
                            }],

                    buttons : [{
                        text : 'Save',
                        handler : function() {
                            var form = this.up('form').getForm();
                            form.submit({
                                        url : saveFormUrl
                                    //  waitMsg : 'Sending the info...',
                                    //  success : function(fp, o) {
                                    //      Ext.Msg.alert('Success',
                                    //              'Form submitted.');
                                    //  }
                                    });
                        }
                    }, {
                        text : 'Cancel'
                    }]
                });
        simple.render(document.body);
        simple.getEl().center();
    });

Controller class:

控制器类:

@Controller
public class UserController {

private static final Logger logger = LoggerFactory
        .getLogger(TController.class);

private TService tService = null;

@Autowired
public void setTService(TService tService) {
    this.tService = tService;
}

@RequestMapping(value = "/index.html", method = RequestMethod.GET)
public String home() {
    System.out.println("Welcome home!");
    return "login";
}

@RequestMapping(value = "/save-form.html", method = RequestMethod.POST)
public ModelAndView submitData(User user){
    System.out.println("User name:"+user.getUserName());
    ModelAndView mv = new ModelAndView("htmlLinks");
    return mv;
}

save-form.html:

保存-form.html:

<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%>
<%@ page session="false"%>
<c:set var="ctx" value="${pageContext.request.contextPath}" />
<html>
<head>
<title>POC</title>

</head>
<body>
 Welcome User !!
</body>
</html>

What am I doing wrong? What is the solution? I am using Ext JS 4 and Spring MVC.

我究竟做错了什么?解决办法是什么?我正在使用 Ext JS 4 和 Spring MVC。

回答by andy

According to the documentationfor form.submit, it looks like the response is requiredto be either JSON or XML, formatted like so:

根据该文档form.submit,它看起来像在响应要求是JSON或XML,格式如下所示:

{
    success: true,
    data: {
        url: "http://somewhere",
        someData: "whatever you want"
    }
}

In your JavaScript's success handler, you can reference o.data.[variable]to get custom data.

在 JavaScript 的成功处理程序中,您可以参考o.data.[variable]以获取自定义数据。

Unfortunately, you will need to change the submitData method(in your controller) to return a JSON response object in the structure defined above. In the response object, you can include a URL to save-form.html. Then you can make an additional GET request for it in the success handler.

不幸的是,您需要更改submitData method(在您的控制器中)以在上面定义的结构中返回一个 JSON 响应对象。在响应对象中,您可以将 URL 包含到save-form.html. 然后,您可以在成功处理程序中为它发出一个额外的 GET 请求。

I don't know if this will work because I have no experience with Ext JS, but I would envision the success handler to look something like this:

我不知道这是否可行,因为我没有使用 Ext JS 的经验,但我希望成功处理程序看起来像这样:

success: function(fp, o) {
    Ext.Msg.alert('Success', 'Form submitted.');
    Ext.Ajax.request({
        url: o.data.url,
        method: "GET",
        success: function(response, request) {
            // do whatever you need to with the generated HTML
            alert(response.responseText);
        },
        failure: function(response, request) {
            alert('failed');
        }
    });
}

回答by tech_enthusiast

Thanks for all replies. I resolved it using the below code.

感谢所有回复。我使用下面的代码解决了它。

buttons : [{ 
    text : 'Save', 
    handler : function() { 
        // The getForm() method returns the 
        // Ext.form.Basic instance: 
        var form = this.up('form').getForm(); 
        form.submit(); 
    } 
}, { 
    text : 'Cancel' 
}]