Java 使用 Jackson 序列化数组
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Serializing array with Hymanson
提问by user86834
I'm serializing the following model:
我正在序列化以下模型：
class Foo {
private List<String> fooElements;
}
If fooElementscontains the strings 'one', 'two' and 'three. The JSON contains one string:
如果fooElements包含字符串“一”、“二”和“三”。JSON 包含一个字符串：
{
"fooElements":[
"one, two, three"
]
}
How can I get it to look like this:
我怎样才能让它看起来像这样：
{
"fooElements":[
"one", "two", "three"
]
}
采纳答案by user86834
I got it working by adding a custom serializer:
我通过添加自定义序列化程序使其工作：
class Foo {
@JsonSerialize(using = MySerializer.class)
private List<String> fooElements;
}
public class MySerializer extends JsonSerializer<Object> {
@Override
public void serialize(Object value, JsonGenerator jgen, SerializerProvider provider)
throws IOException, JsonProcessingException {
List<String> fooList = (List<String>) value;
if (fooList.isEmpty()) {
return;
}
String fooValue = fooList.get(0);
String[] fooElements = fooValue.split(",");
jgen.writeStartArray();
for (String fooValue : fooElements) {
jgen.writeString(fooValue);
}
jgen.writeEndArray();
}
}
回答by nickebbitt
If you are using Hymanson, then the following simple example worked for me.
如果您使用的是 Hymanson，那么以下简单示例对我有用。
Define the Foo class:
定义 Foo 类：
public class Foo {
private List<String> fooElements = Arrays.asList("one", "two", "three");
public Foo() {
}
public List<String> getFooElements() {
return fooElements;
}
}
Then using a standalone Java app:
然后使用独立的 Java 应用程序：
import java.io.IOException;
import org.codehaus.Hymanson.JsonGenerationException;
import org.codehaus.Hymanson.map.JsonMappingException;
import org.codehaus.Hymanson.map.ObjectMapper;
public class JsonExample {
public static void main(String[] args) throws JsonGenerationException, JsonMappingException, IOException {
Foo foo = new Foo();
ObjectMapper mapper = new ObjectMapper();
System.out.println(mapper.writeValueAsString(foo));
}
}
Output:
输出：
{"fooElements":["one","two","three"]}
{"fooElements":["一","二","三"]}
