php fopen中的路径怎么写？
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How to write the path in php fopen?
提问by user1552480
I have some problems with the relative and absolute paths in php fopen. I have the following directories:
我在 php fopen 中的相对和绝对路径有一些问题。我有以下目录：
project:
scripts:
myscript.php
logs:
mylog.log
I want to open mylog.logfrom myscript.phpand I don't know how to specify the path. I tried
我想开mylog.log的myscript.php，我不知道如何指定的路径。我试过
fopen('../logs/mylog.log', "a")
but it won't work. Thanks.
但它不会工作。谢谢。
LE: Thanks for you answers.
LE：谢谢你的回答。
回答by Jeremy Blalock
In php, there are a couple of global constants that could be of help to you. Namely, __DIR__gives you the directory of the current file ('.'just gives you the directory of the root script executing).
在 php 中，有几个全局常量可能对您有所帮助。即，__DIR__为您提供当前文件的目录（'.'只为您提供执行根脚本的目录）。
So what you want is:
所以你想要的是：
fopen(__DIR__ . '/../logs/mylog.log', "a")
回答by Brandon Wamboldt
This should work:
这应该有效：
fopen(__DIR__ . '/../logs/mylog.log', "a");
or in PHP < 5.3:
或在 PHP < 5.3 中：
fopen(dirname(__FILE__) . '/../logs/mylog.log', "a");
回答by Can Geli?
You can use $_SERVER['DOCUMENT_ROOT']which gives the document root of the virtual host.
您可以使用$_SERVER['DOCUMENT_ROOT']which 给出虚拟主机的文档根目录。
eg: $_SERVER['DOCUMENT_ROOT']."/log/mylog.log"
例如： $_SERVER['DOCUMENT_ROOT']."/log/mylog.log"
