C++:读取另一个进程的内存
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C++: reading memory of another process
提问by Forivin
I'd like to have a function that allows me to read the memory of another process. I was thinking about something like this (pseudo code):
我想要一个函数来读取另一个进程的内存。我在想这样的事情(伪代码):
staticAddress = 0x026E0DC4
processId = GetProcessIdByName(processName)
processHandle = GetProcessHandle(processId)
processBaseAddress = GetBaseAddress(processHandle)
addressToRead = processBaseAddress+staticAddress
readValueAsInt = ReadMemoryInt(processHandle, addressToRead)
readValueAsFloat = ReadMemoryFloat(processHandle, addressToRead)
readValueAsString = ReadMemoryString(processHandle, addressToRead)
Would that even be possible? Here is what I got so far:
这甚至可能吗?这是我到目前为止所得到的:
#include <Windows.h>
#include <conio.h>
#include <tlhelp32.h>
#include <string>
#include <psapi.h>
#pragma comment( lib, "psapi" )
int GetProcessId(char* ProcName) {
PROCESSENTRY32 pe32;
HANDLE hSnapshot = NULL;
pe32.dwSize = sizeof( PROCESSENTRY32 );
hSnapshot = CreateToolhelp32Snapshot( TH32CS_SNAPPROCESS, 0 );
if( Process32First( hSnapshot, &pe32 ) ) {
do {
if( strcmp( pe32.szExeFile, ProcName ) == 0 )
break;
} while( Process32Next( hSnapshot, &pe32 ) );
}
if( hSnapshot != INVALID_HANDLE_VALUE )
CloseHandle( hSnapshot );
return pe32.th32ProcessID;
}
int GetModuleBase(HANDLE processHandle, string &sModuleName)
{
HMODULE *hModules;
char szBuf[50];
DWORD cModules;
DWORD dwBase = -1;
//------
EnumProcessModules(processHandle, hModules, 0, &cModules);
hModules = new HMODULE[cModules/sizeof(HMODULE)];
if(EnumProcessModules(processHandle, hModules, cModules/sizeof(HMODULE), &cModules)) {
for(int i = 0; i < cModules/sizeof(HMODULE); i++) {
if(GetModuleBaseName(processHandle, hModules[i], szBuf, sizeof(szBuf))) {
if(sModuleName.compare(szBuf) == 0) {
dwBase = (DWORD)hModules[i];
break;
}
}
}
}
delete[] hModules;
return dwBase;
}
int ReadMemoryInt(HANDLE processHandle, LPCVOID address) {
//LPVOID buffer = ??;
//SIZE_T size = ??;
SIZE_T NumberOfBytesToRead = 4; //??
ReadProcessMemory(processHandle, address, buffer, size, NumberOfBytesToRead)
return buffer; //??
}
int ReadMemoryFloat(HANDLE processHandle, LPCVOID address) {
//LPVOID buffer = ??;
//SIZE_T size = ??;
SIZE_T NumberOfBytesToRead = 8; //??
ReadProcessMemory(processHandle, address, buffer, size, NumberOfBytesToRead)
return buffer; //??
}
int ReadMemoryString(HANDLE processHandle, LPCVOID address) {
//LPVOID buffer = ??;
//SIZE_T size = ??;
SIZE_T NumberOfBytesToRead = 999; //??
ReadProcessMemory(processHandle, address, buffer, size, NumberOfBytesToRead)
return buffer; //??
}
int main()
{
//read an integer from "Program.exe"+0x05D8A3C4
int address = 0x05D8A3C4;
char* processName = "Program.exe";
int processId = GetProcessId(processName);
HANDLE processHandle = OpenProcess(PROCESS_ALL_ACCESS, false, processId);
int processBaseAddress = GetModuleBase(processHandle, (string)"Program.exe";
LPCVOID actualAddress = processBaseAddress+address;
int readValue = ReadMemory(processHandle, actualAddress);
std::cout << readValue << std::endl;
CloseHandle(processHandle);
return 0;
}
As you can see form the question marks in the code I'm really unsure about the "buffer" and "size" parameters of ReadProcessMemory. I'd really appreciate it if someone could help me figuring this out.
从代码中的问号可以看出,我真的不确定 ReadProcessMemory 的“缓冲区”和“大小”参数。如果有人能帮我解决这个问题,我真的很感激。
回答by BeniBela
Here is an example for your ReadMemoryInt()
function:
这是您的ReadMemoryInt()
函数的示例:
int ReadMemoryInt(HANDLE processHandle, LPCVOID address) {
int buffer = 0;
SIZE_T NumberOfBytesToRead = sizeof(buffer); //this is equal to 4
SIZE_T NumberOfBytesActuallyRead;
BOOL err = ReadProcessMemory(processHandle, address, &buffer, NumberOfBytesToRead, &NumberOfBytesActuallyRead);
if (err || NumberOfBytesActuallyRead != NumberOfBytesToRead)
/*an error occured*/ ;
return buffer;
}
The &
mean that the address of the variable is passed instead its value.
这&
意味着传递的是变量的地址而不是它的值。
And in ReadMemoryString()
you cannot know the actual size you need to read, you could either read a big block (size 999) or read many little blocks till you get one containing \0.
在ReadMemoryString()
您无法知道需要读取的实际大小时,您可以读取一个大块(大小为 999)或读取许多小块,直到得到一个包含 \0 的块。
And if you want to know if it works, you can start it in a debugger and look if the values you expect are returned.
如果您想知道它是否有效,您可以在调试器中启动它并查看是否返回了您期望的值。
回答by Forivin
https://github.com/T-vK/Memory-Hacking-Class
Is a pretty simple class to do all that and even more.
Here is a list with all the methods it supports:
https://github.com/T-vK/Memory-Hacking-Class
是一个非常简单的类,可以完成所有这些甚至更多。
这是一个包含它支持的所有方法的列表:
GetProcessId()
GetModuleBase()
SetPrivilege()
GetDebugPrivileges()
ReadInt()
GetPointerAddress()
ReadPointerInt()
ReadFloat()
ReadPointerFloat()
ReadText()
ReadPointerText()
Example usage:
用法示例:
#include "Memory.hpp"
using std::string;
int main() {
char* TARGET_PROCESS_NAME = "League of Legends.exe";
int GAME_VERSION_MODULE_OFFSET = 0x2A1D738; // [Base address of 'League of Legends.exe']+0x2A1D738 (address of a string containing a version number)
Memory Memory;
Memory.GetDebugPrivileges();
int processId = Memory.GetProcessId(TARGET_PROCESS_NAME);
HANDLE processHandle = OpenProcess(PROCESS_ALL_ACCESS, false, processId);
int baseAddress = Memory.GetModuleBase(processHandle, (string)TARGET_PROCESS_NAME);
int gameVersionAddress = baseAddress + GAME_VERSION_MODULE_OFFSET;
string gameVersion = Memory.ReadText(processHandle, gameVersionAddress);
std::cout << "Game version: " << gameVersionAddress << std::endl;
cin.get();
return 0;
}
In case you were wondering, yes, I'm the author.
如果你想知道,是的,我是作者。