Javascript 未捕获的语法错误：JSON.parse 的意外令牌
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Uncaught SyntaxError: Unexpected token with JSON.parse
提问by coiso
what causes this error on the third line?
是什么导致第三行出现此错误？
var products = [{
"name": "Pizza",
"price": "10",
"quantity": "7"
}, {
"name": "Cerveja",
"price": "12",
"quantity": "5"
}, {
"name": "Hamburguer",
"price": "10",
"quantity": "2"
}, {
"name": "Fraldas",
"price": "6",
"quantity": "2"
}];
console.log(products);
var b = JSON.parse(products); //unexpected token oOpen console to view error
打开控制台查看错误
回答by SLaks
productsis an object. (creating from an object literal)
products是一个对象。（从对象文字创建）
JSON.parse()is used to convert a stringcontaining JSON notation into a Javascript object.
JSON.parse()用于将包含 JSON 符号的字符串转换为 Javascript 对象。
Your code turns the object into a string (by calling .toString()) in order to try to parse it as JSON text.
The default .toString()returns "[object Object]", which is not valid JSON; hence the error.
您的代码将对象转换为字符串（通过调用.toString()），以便尝试将其解析为 JSON 文本。
默认.toString()返回"[object Object]"，这是无效的 JSON；因此错误。
回答by EdH
Let's say you know it's valid JSON but your are still getting this...
假设您知道它是有效的 JSON，但您仍然得到这个...
In that case it's likely that there are hidden/special characters in the string from whatever source your getting them. When you paste into a validator, they are lost - but in the string they are still there. Those chars, while invisible, will break JSON.parse()
在这种情况下，字符串中可能存在隐藏/特殊字符，无论您从什么来源获取它们。当您粘贴到验证器中时，它们会丢失 - 但在字符串中它们仍然存在。这些字符虽然不可见，但会破裂JSON.parse()
If sis your raw JSON, then clean it up with:
如果s是您的原始 JSON，则使用以下命令对其进行清理：
// preserve newlines, etc - use valid JSON
s = s.replace(/\n/g, "\n")
.replace(/\'/g, "\'")
.replace(/\"/g, '\"')
.replace(/\&/g, "\&")
.replace(/\r/g, "\r")
.replace(/\t/g, "\t")
.replace(/\b/g, "\b")
.replace(/\f/g, "\f");
// remove non-printable and other non-valid JSON chars
s = s.replace(/[\u0000-\u0019]+/g,"");
var o = JSON.parse(s);
回答by Onur Y?ld?r?m
It seems you want to stringifythe object. So do this:
看来您想对对象进行字符串化。所以这样做：
JSON.stringify(products);
The reason for the error is that JSON.parse()expects a Stringvalue and productsis an Array.
错误的原因是JSON.parse()期望一个String值并且products是一个Array.
Note: I think it attempts json.parse('[object Array]')which complains it didn't expect token oafter [.
注意：我认为它试图json.parse('[object Array]')抱怨它o在[.
回答by Derin
I found the same issue with JSON.parse(inputString).
我发现了同样的问题JSON.parse(inputString)。
In my case the input string is coming from my server page [return of a page method].
在我的情况下，输入字符串来自我的服务器页面[return of a page method]。
I printed the typeof(inputString)- it was string, still the error occurs.
我打印了typeof(inputString)- 它是字符串，仍然发生错误。
I also tried JSON.stringify(inputString), but it did not help.
我也尝试过JSON.stringify(inputString)，但没有帮助。
Later I found this to be an issue with the new line operator [\n], inside a field value.
后来我发现这[\n]是字段值中的 new line operator 的问题。
I did a replace [with some other character, put the new line back after parse]and everything is working fine.
我做了一个替换 [用其他字符，在解析后放回新行]，一切正常。
回答by Térence
JSON.parse is waiting for a String in parameter. You need to stringify your JSON object to solve the problem.
JSON.parse 正在等待参数中的字符串。您需要对 JSON 对象进行字符串化以解决问题。
products = [{"name":"Pizza","price":"10","quantity":"7"}, {"name":"Cerveja","price":"12","quantity":"5"}, {"name":"Hamburguer","price":"10","quantity":"2"}, {"name":"Fraldas","price":"6","quantity":"2"}];
console.log(products);
var b = JSON.parse(JSON.stringify(products)); //solves the problem
回答by pktangyue
products = [{"name":"Pizza","price":"10","quantity":"7"}, {"name":"Cerveja","price":"12","quantity":"5"}, {"name":"Hamburguer","price":"10","quantity":"2"}, {"name":"Fraldas","price":"6","quantity":"2"}];
change to
改成
products = '[{"name":"Pizza","price":"10","quantity":"7"}, {"name":"Cerveja","price":"12","quantity":"5"}, {"name":"Hamburguer","price":"10","quantity":"2"}, {"name":"Fraldas","price":"6","quantity":"2"}]';
回答by hoogw
You should validate your JSON string here.
您应该在此处验证您的 JSON 字符串。
A valid JSON string must have double quotes around the keys:
有效的 JSON 字符串必须在键周围使用双引号：
JSON.parse({"u1":1000,"u2":1100}) // will be ok
If there are no quotes, it will cause an error:
如果没有引号，则会导致错误：
JSON.parse({u1:1000,u2:1100})
// error Uncaught SyntaxError: Unexpected token u in JSON at position 2
Using single quotes will also cause an error:
使用单引号也会导致错误：
JSON.parse({'u1':1000,'u2':1100})
// error Uncaught SyntaxError: Unexpected token ' in JSON at position 1
回答by att
If there are leading or trailing spaces, it'll be invalid. Trailing/Leading spaces can be removed as
如果有前导或尾随空格，则无效。尾随/前导空格可以删除为
mystring = mystring.replace(/^\s+|\s+$/g, "");
Source: http://www.toptip.ca/2010/02/javascript-trim-leading-or-trailing.html
资料来源：http: //www.toptip.ca/2010/02/javascript-trim-leading-or-trailing.html
回答by tmurphree
Here's a function I made based on previous replies: it works on my machine but YMMV.
这是我根据以前的回复制作的一个功能：它适用于我的机器，但 YMMV。
/**
* @description Converts a string response to an array of objects.
* @param {string} string - The string you want to convert.
* @returns {array} - an array of objects.
*/
function stringToJson(input) {
var result = [];
//replace leading and trailing [], if present
input = input.replace(/^\[/,'');
input = input.replace(/\]$/,'');
//change the delimiter to
input = input.replace(/},{/g,'};;;{');
// preserve newlines, etc - use valid JSON
//https://stackoverflow.com/questions/14432165/uncaught-syntaxerror-unexpected-token-with-json-parse
input = input.replace(/\n/g, "\n")
.replace(/\'/g, "\'")
.replace(/\"/g, '\"')
.replace(/\&/g, "\&")
.replace(/\r/g, "\r")
.replace(/\t/g, "\t")
.replace(/\b/g, "\b")
.replace(/\f/g, "\f");
// remove non-printable and other non-valid JSON chars
input = input.replace(/[\u0000-\u0019]+/g,"");
input = input.split(';;;');
input.forEach(function(element) {
// console.log(JSON.stringify(element));
result.push(JSON.parse(element));
}, this);
return result;
}
回答by San
[
{
"name": "Pizza",
"price": "10",
"quantity": "7"
},
{
"name": "Cerveja",
"price": "12",
"quantity": "5"
},
{
"name": "Hamburguer",
"price": "10",
"quantity": "2"
},
{
"name": "Fraldas",
"price": "6",
"quantity": "2"
}
]
Here is your perfect Json that you can parse.
这是您可以解析的完美 Json。
