C++ 如何创建 const char* 的静态 const 数组
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How to create a static const array of const char*
提问by Tommy
I tried the following line:
我尝试了以下行：
static const const char* values[];
But I get the following warning on VC++ warning C4114:
但是我在 VC++ 警告 C4114 上收到以下警告：
same type qualifier used more than once.
多次使用相同类型的限定符。
What is the correct declaration? The goal is to create an immutable array of c strings.
什么是正确的声明？目标是创建一个不可变的 c 字符串数组。
回答by Mesop
You wrote const constinstead of static const char* const values[];(where you define the pointer and the underlying values as const)
您编写了const const而不是static const char* const values[];（您将指针和基础值定义为const）
Also, you need to initialize it:
此外，您需要对其进行初始化：
static const char* const values[] = {"string one", "string two"};
static const char* const values[] = {"string one", "string two"};
回答by Attila
Try
尝试
static const char* const values[];
The idea is to put the two consts on either side of *: the left belongs to char(constant character), the right belongs to char*(constant pointer-to-character)
这个想法是把两个consts 放在两边*：左边属于char（常量字符），右边属于char*（常量指针到字符）
