Javascript ES6`从导入导出*？
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ES6 `export * from import`?
提问by Jordan Feldstein
Is there a syntax using ES6 or ES7 or babel which will allow me to easily bundle together many groups of sub files?
是否有使用 ES6 或 ES7 或 babel 的语法可以让我轻松地将多组子文件捆绑在一起？
E.g., given:
例如，给定：
./action_creators/index.js
./action_creators/foo_actions.js
./action_creators/bar_actions.js
Have index.js import foo and bar actions, then re-export them, so I can
让 index.js 导入 foo 和 bar 动作，然后重新导出它们，这样我就可以
import {FooAction, BarAction} from './action_creators/index.js'
I don't want to have to remember / change references if I were to change which file I've organized the objects themselves into.
如果我要更改将对象本身组织到哪个文件中，我不想必须记住/更改引用。
回答by Timo
Yes, ES6 supports directly exporting imported modules:
是的，ES6 支持直接导出导入的模块：
export { name1, name2, …, nameN } from …;
export {FooAction, BarAction} from './action_creators/index.js'
You can also re-export all exportsof the imported module using the *syntax:
您还可以使用以下语法重新导出导入模块的所有导出*：
export * from …;
export * from './action_creators/index.js';
回答by Gerson Diniz
Defaultexport as Default:
默认导出为Default：
export {default} from './something';
Defaultexport as Named:
默认导出为Named：
export {default as foo} from './something';
Namedexport as Default:
命名导出为默认：
export {foo as default} from './something';
Namedexport as Named:
命名导出为Named：
export {foo} from './something';
