Javascript 将回调函数传递给 jQuery AJAX 成功函数
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Passing a callback function to jQuery AJAX success function
提问by Brett
I'm trying to pass in a function to run when the AJAX call is successful, however it's not working as it say's that "callback is not a function".
我试图传入一个函数以在 AJAX 调用成功时运行，但是它不起作用，因为它说“回调不是函数”。
Example:
例子：
Calling Code:
调用代码：
getGrades(var);
JS:
JS：
function getGrades(grading_company) {
// Set file to get results from..
var loadUrl = "ajax_files/get_grades.php";
// Set data string
var dataString = 'gc_id=' + grading_company;
// Set the callback function to run on success
var callback = 'showGradesBox';
// Run the AJAX request
runAjax(loadUrl, dataString, callback);
}
function showGradesBox(response) {
// Code here...
}
function runAjax(loadUrl, dataString, callback) {
jQuery.ajax({
type: 'GET',
url: loadUrl,
data: dataString,
dataType: 'html',
error: ajaxError,
success: function(response) {
callback(response);
}
});
}
Now if I replace this line below with the function name itself it works:
现在，如果我用函数名称本身替换下面的这一行，它会起作用：
callback(response);
But I can't get it to work like above where I get the function name from a passed in parameter.
但是我不能像上面那样工作，我从传入的参数中获取函数名称。
回答by micha
showGradesBoxis a string in your code. So you have two options to execute the callback function:
showGradesBox是代码中的字符串。所以你有两个选项来执行回调函数：
If you want to keep the string you can use
如果你想保留你可以使用的字符串
this[callback](response);
(if callbackis defined in global scope you can also use window[callback](response);
（如果callback在全局范围内定义，您也可以使用window[callback](response);
Or you can pass the function directly:
或者你可以直接传递函数：
var callback = showGradesBox;
(in this case you can keep your existing code for callback execution)
（在这种情况下，您可以保留现有代码用于回调执行）
