C# 将参数传递给 XSLT 样式表
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Pass parameter to XSLT stylesheet
提问by coson
I'm trying to pass a couple of parameters to an XSLT style sheet. I have followed the example: Passing parameters to XSLT Stylesheet via .NET.
我正在尝试将几个参数传递给 XSLT 样式表。我遵循了这个例子:通过 .NET 将参数传递给 XSLT 样式表。
But my transformed page is not correctly displaying the value.
但是我转换后的页面没有正确显示该值。
Here is my C# code. I had to add a custom function to perform some arithmetic because Visual Studio 2010 doesn't use XSLT 2.0.
这是我的 C# 代码。我不得不添加自定义函数,因为Visual Studio 2010中不使用XSLT 2.0来执行一些算术。
var args = new XsltArgumentList();
args.AddExtensionObject("urn:XslFunctionExtensions", new XslFunctionExtensions());
args.AddParam("processingId", string.Empty, processingId);
var myXPathDoc = new XPathDocument(claimDataStream);
var xslCompiledTransformation = new XslCompiledTransform(true);
// XSLT File
xslCompiledTransformation.Load(xmlReader);
// HTML File
using (var xmlTextWriter = new XmlTextWriter(outputFile, null))
{
xslCompiledTransformation.Transform(myXPathDoc, args, xmlTextWriter);
}
Here is my XSLT:
这是我的 XSLT:
<xsl:template match="/">
<xsl:param name="processingId"></xsl:param>
..HTML..
<xsl:value-of select="$processingId"/>
Am I missing something?
我错过了什么吗?
采纳答案by Dimitre Novatchev
Here is my XSLT:
<xsl:template match="/"> <xsl:param name="processingId"></xsl:param> ..HTML.. <xsl:value-of select="$processingId"/>Am I missing something?
这是我的 XSLT:
<xsl:template match="/"> <xsl:param name="processingId"></xsl:param> ..HTML.. <xsl:value-of select="$processingId"/>我错过了什么吗?
Yes, you are missing the fact that the invoker of an XSLT transformation can set the values of global-levelparameters -- not the values of template-level parameters.
是的,您忽略了一个事实,即 XSLT 转换的调用者可以设置全局级参数的值——而不是模板级参数的值。
Therefore, the code must be:
因此,代码必须是:
<xsl:param name="processingId"/>
<xsl:template match="/">
..HTML..
<xsl:value-of select="$processingId"/>
<!-- Possibly other processing here -->
</xsl:template>

