php Laravel:刀片视图中未定义的变量
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/43111519/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Laravel: Undefined variable in blade view
提问by Sahand
This is AdminController.php
:
这是AdminController.php
:
<?php
namespace App\Http\Controllers;
use Response;
use Illuminate\Support\Facades\DB;
use App\Caption;
use App\Image;
use App\Http\Controllers\Controller;
class AdminController extends Controller
{
public function admin() {
$images = Image::paginate();
return view('admin',[ '$images' => $images]);
}
}
And this is admin.blade.php
:
这是admin.blade.php
:
@extends('template')
@section('title')
Admin Page
@endsection
@section('header')
@endsection
@section('main')
@if (Auth::check())
@foreach ($images as $image)
<p value='{{$image->id}}'>{{$image->content}}</p>
<form action="image/{{$image->id}}/delete" method="post">
<button type="submit">Delete caption</button>
</form>
<form action="image/{{$image->id}}/approve" method="post">
<button type="submit">Accept image</button>
</form>
@endforeach
@else
<p>Login first</p>
@endif
@endsection
@section('footer')
@endsection
Why do I get the following error?
为什么会出现以下错误?
ErrorException in 408148d5409ae6eebf768dc5721bd0d1d9af48af.php line 9: Undefined variable: images (View: /Users/sahandz/Documents/School/Singapore/CS3226/backend/resources/views/admin.blade.php)
ErrorException in 408148d5409ae6eebf768dc5721bd0d1d9af48af.php 第 9 行:未定义变量:图像(视图:/Users/sahandz/Documents/School/Singapore/CS3226/backend/resources/views/admin.blade.php)
$images
is clearly defined in my controller.
$images
在我的控制器中明确定义。
回答by Joe
You have used $images
as your variable name when passing the data to the view. This results in blade creating a variable called $$images
.
$images
将数据传递给视图时,您已将其用作变量名。这导致刀片创建一个名为 的变量$$images
。
return view('admin',[ 'images' => $images]);
will result in the view creating a variable called $images
将导致视图创建一个名为的变量 $images
回答by Rehan
Try passing data like this.
尝试像这样传递数据。
$images = Image::paginate();
return view("admin")->with('images',$images);
Basically,you need not use $
in the variable name.
基本上,您不需要$
在变量名中使用。
回答by Abdullah Al Shakib
Your code should be like this
你的代码应该是这样的
public function admin() {
$images = Image::paginate();
return view('admin',[ 'images' => $images]);
}
}
Why you use [ '$images' => $images]
. that is the problem.
为什么你使用[ '$images' => $images]
. 那就是问题所在。
回答by ram pratap singh
You may use this method also to pass your data to view
您也可以使用此方法将数据传递给查看
return view('admin',compact('images'));