C语言 json数组在c中解析

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时间:2020-09-02 06:36:58  来源:igfitidea点击:

json array parsing in c

carraysjsonparsing

提问by lenin T.mohan

i am trying to parse a json array,i am facing problem.

我正在尝试解析一个 json 数组,我遇到了问题。

My array is like this:

我的数组是这样的:

configure: {
  "id": 4,
  "userId": 107,
  "deviceMacAddress": "00:06:66:30:02:3C",
  "medication": [{
    "id": 11,
    "version": 18,
    "name": "name1",
    "unit": "mg",
    "forMed": "for1",
    "schedule": [1]
  }, {
  "id": 45,
  "version": 1,
  "name": "sdga",,
  "unit": "mg",
  "forMed": "54234",
  "schedule": [0,1,2,3,4,5,6]
  }],

i am able to access medication array and print total array,but not able to access objects inside array. can you pls suggest any solution or any example to do this using C language?

我能够访问药物数组并打印总数组,但无法访问数组内的对象。你能建议任何解决方案或任何例子来使用 C 语言来做到这一点吗?

MyCode

我的代码

int main(int argc, char **argv) {
  struct json_object *med_obj, *medi_obj, *tmp1_obj;
  struct array_list *lArray;
  charname[10] = {0};
  static const char filename[] = "xyz.txt";
  med_obj = json_object_from_file(filename);
  medi_obj = json_object_object_get(med_obj, "medication");
  lArray = json_object_get_array(medi_obj);
  tmp1_obj = json_object_object_get(medi_obj, "name");
  strcpy (name,json_object_to_json_string(tmp1_obj));
  printf("name=%s\n",name);
}

Regards, Lenin.

问候,列宁。

回答by Aiias

You need to access the inner array using a json_object *variable.

您需要使用json_object *变量访问内部数组。

Try this:

尝试这个:

struct json_object *med_obj, *medi_array, *medi_array_obj, *medi_array_obj_name;
int arraylen, i;
charname[10] = {0};
static const char filename[] = "xyz.txt";
med_obj = json_object_from_file(filename);
medi_array = json_object_object_get(med_obj, "medication");

// medi_array is an array of objects
arraylen = json_object_array_length(medi_array);

for (i = 0; i < arraylen; i++) {
  // get the i-th object in medi_array
  medi_array_obj = json_object_array_get_idx(medi_array, i);
  // get the name attribute in the i-th object
  medi_array_obj_name = json_object_object_get(medi_array_obj, "name");
  // print out the name attribute
  printf("name=%s\n", json_object_get_string(medi_array_obj_name));
}

回答by spmno

You can use the jsoncpp to do this job. Array as a Json::Value, you can

您可以使用 jsoncpp 来完成这项工作。数组作为 Json::Value,你可以

medicationValue = jsonObject[medicationKey];
Json::Value::Members member;
member = medicationValue .getMemberNames();

for (Json::Value::Members::iterator iter = member.begin(); iter != member.end(); iter++) {
    the element of medication here
}

I hope will help you.

我希望能帮到你。

回答by leonhart

If you want to access the array as a json object, you should get it as a json_object* but not a array_list*

如果要将数组作为 json 对象访问,则应将其作为 json_object* 而不是 array_list*

struct json_object *lArray; 
...
lArray=json_object_get(medi_obj); 
tmp1_obj = json_object_object_get(json_object_array_get_idx(lArray, 0), "name");

回答by Vasily Redkin

You can use any YAMLparsing library, look herefor example.

您可以使用任何YAML解析库,例如查看此处